MCQ
When a particle moving in a circular orbit of radius 6.28 meters reaches from one end of the diameter to the other, then the ratio between the distance covered and the displacement will be :
- A$2 \pi$
- B$\frac{\pi}{2}$
- ✓$\pi$
- D1
✓
Answer
Correct option: C.
$\pi$
(c) $\frac{\text { Distance }}{\text { Displacement }}=\frac{\pi r}{2 r}=\frac{\pi}{2}$
Therefore, the correct option is (c).
Therefore, the correct option is (c).
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A car moves from $X$ to $Y$ with a uniform speed $v_1$ and returns to $Y$ with a uniform speed $v_2$ . The average speed for this round trip is
→A spring block system is placed on a rough horizontal floor. The block is pulled towards right to give spring some elongation and released.
$Assertion$ : For the planets orbiting around the sun, angular speed, linear speed and $K.E.$ changes with time, but angular momentum remains constant.
$Reason$ : No torque is acting on the rotating planet. So its angular momentum is constant.
→$Reason$ : No torque is acting on the rotating planet. So its angular momentum is constant.
Two planets revolve round the sun with frequencies ${N_1}$ and ${N_2}$ revolutions per year. If their average orbital radii be ${R_1}$ and ${R_2}$ respectively, then ${R_1}/{R_2}$ is equal to
→In Melde's experiment, the string vibrates in $4$ loops when a $50 \,gram$ weight is placed in the pan of weight $15\, gram.$ To make the string to vibrates in $6$ loops the weight that has to be removed from the pan is
→At the top of the trajectory of a projectile, the directions of its velocity and acceleration are
The wave length of light in visible part $({\lambda _V})$ and for sound $({\lambda _S})$ are related as
→The power of a windmill having blade area equal to $A$ and wind velocity equal to $v$ is $(\rho$ is density of air$):$
→A body of mass $1\,kg$ crosses a point $O$ with a velocity $60\,ms^{-1}.$ A force of $10\,N$ directed towards $O$ begins to act on it. It will again cross $O$ in ........ $\sec$
→The surface tension of liquid is $0.5\, N/m$. If a film is held on a ring of area $0.02 \,m^2$, its surface energy is
→