When a resistance of $5\,\Omega$ is shunted with a moving coil galvanometer, it shows a full scale deflection for a current of $250\,mA$, however when $1050\,\Omega$ resistance is connected with it in series, it gives full scale deflection for $25$ volt. The resistance of galvanometer is $......\,\Omega$.
JEE MAIN 2023, Diffcult
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$\frac{250\,mA \times 5}{5+R_G}=i \dots(i)$
$i=\frac{25}{1050+R_G} \dots(ii)$
From $(i)$ and $(ii)$
$\frac{25}{1050+R_G}=\frac{5}{4\left(5+R_G\right)}$
$100\left(5+R_G\right)=1050 \times 5+R_G \times 5$
$95 R_G=4750$
$R_G=50\,\Omega$
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