$ \therefore \frac{i_2}{i_1}=\frac{\theta_2}{\theta_1} \Rightarrow \frac{i_2}{200 \mu \mathrm{A}}=\frac{\pi / 10}{\pi / 3}=\frac{3}{10}$
$ \Rightarrow \mathrm{i}_2=60\ \mu \mathrm{A}$

$\vec E = 2\hat i + 3\hat j ;\, B = 4\hat j + 6\hat k$
The charged particle is shifted from the origin to the point $P(x = 1 ;\, y = 1)$ along a straight path. The magnitude of the total work done is
