When $F = 2N$, the frictional force between $5 kg$ block and ground is ...... $N$
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$\mathrm{F}_{1} \mathrm{max}=0.1 \times 10 \times 10=10 \mathrm{N}$
$\mathrm{F}_{2} \max =0.3 \times 15 \times 10=45 \mathrm{N}$
For $\mathrm{F}=2 \mathrm{N},$ static friction come in to play at both surfaces.
$\therefore F=F_{2}$
$\therefore F_{2}=2 N$
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