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Two identical coils of radius $R$ and number of turns $N$ are placed perpendicular to each others in such a way that they have common centre. The current through them are $I$ and $I\sqrt 3$ . The resultant intensity of magnetic field at the centre of the coil will be (in $weber/m^2)2$
The magnetic field at the centre of a circular current carrying-conductor of radius $r$ is $B_c$. The magnetic field on its axis at a distance $r$ from the centre is $B_a$. The value of $B_c : B_a$ will be :-
A Helmholtz coil has pair of loops, each with $N$ turns and radius $R$. They are placed coaxially at distance $R$ and the same current $I$ flows through the loops in the same direction. The magnitude of magnetic field at $P$, midway between the centres $A$ and $C$, is given by (Refer to figure)
A long, straight wire is turned into a loop of radius $10\,cm$ (see figure). If a current of $8\, A$ is passed through the loop, then the value of the magnetic field and its direction at the centre $C$ of the loop shall be close to
A uniform magnetic field of $2 \times 10^{-3} \mathrm{~T}$ acts along positive $\mathrm{Y}$-direction. A rectangular loop of sides $20$ $\mathrm{cm}$ and $10 \mathrm{~cm}$ with current of $5 \mathrm{~A}$ is $\mathrm{Y}-\mathrm{Z}$ plane. The current is in anticlockwise sense with reference to negative $\mathrm{X}$ axis. Magnitude and direction of the torque is :