ઇથેનોલના મોલ \(=\frac{69}{16}=\frac{3}{2}\)
ઇથેનોલના મોલ-અંશ \(=0.6=\frac{\frac{3}{2}}{\frac{1}{18}+\frac{3}{x}}\)
\(\therefore \frac{3}{5}=\frac{27}{x+27}\)
\(\therefore 3 x+81=135\)
\(\therefore x=\frac{135-81}{3}=\frac{54}{3}\)
\(\quad=18\,g\)