MCQ
$x{A_{\left( s \right)}}\, \rightleftharpoons \,y{B_{(g)}} + z{C_{(g)}}$ If $\frac{{{k_c}}}{{{k_p}}}\, = {(RT)^{ - 2}},$ then which is correct
- A$y + z -x = -2$
- B$y + z -x = 2$
- C$y + z = -2$
- ✓$y + z = 2$
✓
Answer
Correct option: D.
$y + z = 2$
d
${{\text{K}}_i} = {{\text{K}}_{\text{c}}} \times {({\text{RT}})^{\Delta {n_g}}}$
${{\text{K}}_i} = {{\text{K}}_{\text{c}}} \times {({\text{RT}})^{\Delta {n_g}}}$
$\frac{{{K_i}}}{{{K_c}}} - {({\text{RT}})^{1/5}}$
Gruen $ = \frac{{{{\text{K}}_c}}}{{{{\text{K}}_{\text{i}}}}} - {({\text{RT}})^{ - 2}} \Rightarrow \frac{{{{\text{K}}_i}}}{{{{\text{K}}_{\text{c}}}}} - {({\text{RT}})^2}$
$\therefore \quad \Delta \mathrm{n}_{\mathrm{g}}=2$
$\quad \mathrm{y}+\mathrm{z}=2$
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