Question
यदि $f(x) = {x^2} + 4x + 1$ तब
$f(x) \ge 1 \Rightarrow {x^2} + 4x + 1 \ge 1\, \Rightarrow {x^2} + 4x \ge 0$
$x \le - 4$या $x \ge 0$.
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