Question
यदि $\int_{}^{} {\frac{{f(x)\;dx}}{{\log \sin x}} = \log \log \sin x} $, तब $f(x) = $
दोनों पक्षों का अवकलन करने पर
$\frac{{f(x)}}{{\log \sin x}} = \frac{{\cot x}}{{\log \sin x}} \Rightarrow f(x) = \cot x.$
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$\tan ^{-1} \frac{1-x}{1+x}=\frac{1}{2} \tan ^{-1} x,(x>0)$
$(A)$ $5$ $(B)$ $7$ $(C)$ $\frac{-15}{2}$ $(D)$ $\frac{-17}{2}$