यदि $\int_{}^{} {x\sin xdx = - x\cos x + A} $, तब $A = $
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Answer
a (a) Since,$\int_{}^{} {x\sin x\,dx} = - x\cos x + A$
$ \Rightarrow - x\cos x + \sin x + {\rm{}}अचर= - x\cos x + A$
तुलना करने पर, $A = \sin x + {\rm{}}{\rm{.}}$अचर
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