Question
यदि ${\left| {\,\begin{array}{*{20}{c}}4&1\\2&1\end{array}\,} \right|^2} = \left| {\,\begin{array}{*{20}{c}}3&2\\1&x\end{array}\,} \right| - \left| {\,\begin{array}{*{20}{c}}x&3\\{ - 2}&1\end{array}\,} \right|$,तो $x $ का मान होगा
$ = \left| {\,\begin{array}{*{20}{c}}{17}&9\\9&5\end{array}\,} \right| = (3x - 2) - (x + 6)$
==> $85 - 81 = 2x - 8$
==> $4 + 8 = 2x$
==> $x = 6$.
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