Question
योगफल $\sum_{n=1}^{21} \frac{3}{(4 n-1)(4 n+3)}$ बराबर है
$=\frac{3}{4}\left[\left(\frac{1}{3}-\frac{1}{7}\right)+\left(\frac{1}{7}-\frac{1}{11}\right)+\ldots .+\left(\frac{1}{83}-\frac{1}{87}\right)\right]$
$=\frac{3}{4}\left[\frac{1}{3}-\frac{1}{87}\right]=\frac{3}{4} \frac{84}{3.87}=\frac{7}{29}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.