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MATHS 2 Marks Questions

Factorisation · Bihar Board (BSEB) STD 8 (BSEB - English Medium). 110 questions.

Questions · Page 3 of 3

2 Marks Questions

Question 1012 Marks
Factorise:
$6 x^2-17 x-3$
Answer
$6 x^2-17 x-3$
$=6 x^2-18 x+x-3$
$\{6 × (-3) = -18, -18 = -18 × 1, -17 = -18 + 1\}$
$= 6x(x - 3) + 1(x - 3)$
$ = (x - 3)(6x + 1)$
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Question 1022 Marks
Factorise:
$x^2+5 x+6$
Answer
$x^2+5 x+6$
$=x^2+2 x+3 x+6$
$\{6 = 2 × 3, 5 = 2 + 3\}$
$= x(x + 2) + 3(x + 2)$
$ = (x + 2)(x + 3)$
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Question 1032 Marks
Factorise:
$=16 a^2-225 b^2$
Answer
Using: $a^2-b^2$
$=(a+b)(a-b)$
$=16 a^2-225 b^2$
$=(4 a)^2-(15 b)^2$
$=(4 a+15 b)(4 b-15 b)$
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Question 1042 Marks
Factorise:
$z^2+19 z-150$
Answer
$z^2+19 z-150$
$=z^2+25 z-6 z-150$
$\{-150 = 25 × (-6), 19 = 25 - 6\}$
$= z(z + 25) - 6(z + 25)$
$ = (z + 25)(Z - 6)$
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Question 1052 Marks
Factorise:
$7 y^2-19 y-6$
Answer
$7 y^2-19 y-6$
$=7 y^2-21 y+2 y-6$
$\{7 × (-6) = -42, -42 = -21 × 2, -19 = -21 + 3\}$
$= 7y(y - 3) + 2(y - 3) $
$= (y - 3)(7y + 2)$
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Question 1062 Marks
Factorise:
$x^2-9 x+20$
Answer
$x^2-9 x+20$
$=x^2-5 x-4 x+20$
$\{20 = (-5) × (-4), -9 = -5 - 4\}$
$= x(x - 5) - 4(x - 5)$
$ = (x - 5)(x - 4)$
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Question 1072 Marks
Factorise:
$p^2+6 p+8$
Answer
$p^2+6 p+8$
$=p^2+4 p+2 p+8$
$\{8 = 4 × 2, 6 = 4 + 2\}$
$ = p(p + 4) + 2(p + 4) $
$= (p + 4)(p + 2)$
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Question 1082 Marks
Factorise:
$121 a^2-88 a b+16 b^2$
Answer
$121 a^2-88 a b+16 b^2$
$=(11 a)^2-2 \times 11 a \times 4 b+4(b)^2$
$=(11 a-4 b)^2$
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Question 1092 Marks
Factorise:
$2 x^2-17 x-30$
Answer
$2 x^2-17 x-30$
$=2 x^2-20 x+3 x-30$
$\{2 × (-30) = -60, -17 = -20 + 3, -60 = -20 × 3\}$
$= 2x(x - 10) + 3(x - 10) $
$= (x - 10)(2x + 3)$
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2 Marks Questions - Page 3 - MATHS STD 8 Questions - Vidyadip