M.C.Q

MCQ 511 Mark

Find the value of k, if $x = 1, y = 2$ is a solution of the equation $2x + 3y = k.$

A
$5$
B
$6$
C
$7$
✓
$8$

Answer

Correct option: D.

$8$

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MCQ 521 Mark

The equation $y = 2x - 7$ has:

✓
Many solutions.
B
No solution.
C
Two solutions.
D
One solution.

Answer

Correct option: A.

Many solutions.

$y = 2x - 7$Has many solutions because for different value of $x$ we have different value of $y$ for example.
At $x = 1$
$y = 2 (1) - 7$
$y = 2 - 7$
$y = -5$
At $x = 2$
$y = 2(2) - 7$
$y = 4 - 7$
$y = -3$
So we can say for many value of $x$ there is many value of $y.$

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MCQ 531 Mark

The graph of $x + 3 = 0$ is a line.

A
Making an intercept $-3$ on the $y-$axis.
B
Parallel to the $x-$axis at a distance of $3$ units below the $x-$axis.
✓
Making an intercept $-3$ on the $x-$axis.
D
Parallel to the $y-$axis at a distance of $3$ units to the left of $y-$axis.

Answer

Correct option: C.

Making an intercept $-3$ on the $x-$axis.

As, the graph of $x+3=0$ or $x=-3$ is a line parallel to $y$-axis i.e. $x=0$.
$\Rightarrow$ The line represented by the equation $x=-3$ is parallel to $y$-axis and intersects $x$-axis at $x=-3$.
So, the graph of $x+3=0$ is a line parallel to the $y$-axis at a distance of 3 units to the left of $y$-axis making an intercept -3 on the $x$-axis.

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MCQ 541 Mark

The equation of a line parallel to $x-$axis and $3$ units above the origin is:

A
$x = 3$
✓
$y = 3$
C
$x = -3$
D
$y = -3$

Answer

Correct option: B.

$y = 3$

The equation of a line parallel to $x$-axis and $3$ units above the origin is $y=3$.
Because when a line parallel to $x$ axis in that case equation of line is $y=a$
where $a$ is the co-ordinate of $y$-axis and $3$ units above the origin value $x$-coordinate is $3$ so required equation is $y=3$.

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MCQ 551 Mark

The equation of a line parallel to $y-$axis and $7$ units to the left of origin is:

✓
$x = -7$
B
$y = 7$
C
$y = -7$
D
$x = 7$

Answer

Correct option: A.

$x = -7$

The equation of a line parallel to $y$-axis and $7$ units to the left of the origin is $x=-7$. Because when a line parallel to $y$-axis in that case equation of line is $x=a$.
Where $a$ is the co-ordinate of $x$-axis and $7$ units to the left of the origin value $x$-co-ordinate is $-7$ .
So required equation is $x=-7$.

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MCQ 561 Mark

Any solution of the linear equation $2x + 0y + 9 = 0$ in two variables is of the form:

A
$\Big(0,-\frac{9}{2}\Big)$
B
$(-9,0)$
C
$\Big(\text{n},-\frac{9}{2}\Big)$
✓
$\Big(-\frac{9}{2},\text{m}\Big)$

Answer

Correct option: D.

$\Big(-\frac{9}{2},\text{m}\Big)$

$2x + 9 = 0 \Rightarrow\text{x}=\frac{-9}{2}$ And $y = m$, where m is any real number,
Hence, $\Big(-\frac{9}{2},\text{m}\Big)$ is the solution of the given equation.

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MCQ 571 Mark

The linear equation $2x - 5y = 7$ has:

A
Two solutions.
✓
Infinitely many solutions.
C
No solution.
D
A unique solution.

Answer

Correct option: B.

Infinitely many solutions.

Given equation is $2x - 5y = 7$,There is no given value of $x$ and $y$ so we can take any values. For every value of $x$, we get a corresponding value of $y$ and vice-versa.
Therefore, it has infinitely many solutions.

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MCQ 581 Mark

Write the correct answer in the following: The positive solutions of the equation $ax + by + c = 0$ always lie in the,

✓
I$^{st}$ quadrant.
B
II$^{nd}$ quadrant.
C
III$^{rd}$ quadrant.
D
IV$^{th}$ quadrant.

Answer

Correct option: A.

I$^{st}$ quadrant.

We know that, if a line passes through the Ist quadrant, then all solution lying on the line in first quadrant must be positive because the coordinate of all points in the Ist quadrant are positive.

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MCQ 591 Mark

The point on the graph of the linear equation $2x + 5y = 19$, whose ordinate is $1^{\frac{1}{2}}$ times its abscissa is:

A
$(-2, -3)$
✓
$(2, 3)$
C
$(4, 6)$
D
None of these.

Answer

Correct option: B.

$(2, 3)$

Ordinate means y-coordinate. It means we need to find a point on the given line where y-coordinte $=\frac{3}{2}$ ex-coordinate).Just put $\text{y}=\Big[\frac{3}{2}\Big].\text{x}$ in the given eqn.
$2\text{x}+5\times\frac{3}{2}\text{x}=19$
$2\text{x}+\frac{15}{2}\text{x}=19$
$\frac{19\text{x}}{2}=19$
$\text{x}=\frac{19\times2}{19}$
$\text{y}=\frac{3}{2}\text{x}$
$\text{y}=\frac{3}{2}\times2$
$\text{y}=3$
So the co-ordinate are $(2, 3)$

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MCQ 601 Mark

How many lines pass through one point?

A
Two.
B
Three.
✓
Many.
D
One.

Answer

Correct option: C.

Many.

Because one point can be solution of many equations. So many equations can be pass from one point.

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MCQ 611 Mark

For the equation $5x + 8y = 50$, if $y = 10$, then the value of $x$ is:

✓
$-6$
B
$-12$
C
$6$
D
$12$

Answer

Correct option: A.

$-6$

For the equation $5x + 8y = 50$, if $y = 10$
Put $y = 10$ in given equation
$5x + 8 × 10 = 50$
$5x + 80 = 50$
$5x = 50 - 80$
$5x = -30$
$\text{x} = -\frac{30}{5}$
$x = -6$

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MCQ 621 Mark

The graph of the linear equation $y = 3x$ passes through the point.

A
$(0,-\frac{2}{3})$
✓
$(\frac{2}{3},2)$
C
$(,-\frac{2}{3},0)$
D
$(0,\frac{2}{3})$

Answer

Correct option: B.

$(\frac{2}{3},2)$

$\text{y}=3\text{x}$
$\frac{\text{y}}{3}=\text{x}$
For $\text{x}=\frac{2}{3},$ the value of $\text{y}=3\times\frac{2}{3}=2$
So $(\frac{2}{3},2).$

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MCQ 631 Mark

Any point on the $y -$ axis is of the form.

A
$(y, y)$
✓
$(0, y)$
C
$(x, y)$
D
$(x, 0)$

Answer

Correct option: B.

$(0, y)$

Any point on the $y -$ axis is of the form $(0, y).$
On the $y$ - axis, $y$ can take any values and $x$ should be equal to $0.$

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MCQ 641 Mark

Which of the following is the equation of a line parallel to $y -$ axis?

A
$y = 0$
B
$x + y = z$
C
$y = x$
✓
$x = a$

Answer

Correct option: D.

$x = a$

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MCQ 651 Mark

If the graph of the equation $4x + 3y = 12$ cuts the coordinate axes at $A$ and $B$, then hypotenuse of right triangle $AOB$ is of length.

A
$3$ units.
B
$4$ units.
✓
$5$ units.
D
None of these.

Answer

Correct option: C.

$5$ units.

According to the given question, triangle so formed has sides of units $3$ and $4$, using pythagoras theorem, the largest side is of $5$ units.

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MCQ 661 Mark

If $(2k - 1, k)$ is a solution of the equation $10x - 9y = 12$, then $k =$

A
$1$
✓
$2$
C
$3$
D
$4$

Answer

Correct option: B.

$2$

If $(2k - 1, k)$ is solution of equation $10x - 9y = 12$, then it must satisfy this equation.
Thus, we have
$10(2k - 1) - 9k = 12$
$20k - 10 - 9k = 12$
$11k = 22$
$k = 2$
Hence, correct option is $(b).$

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MCQ 671 Mark

$x = 5$ and $y = -2$ is the solution of the linear equation.

A
$x + 3y = 1$
B
$2x + y = 9$
C
$3x + y = 0$
✓
$2x - y = 12$

Answer

Correct option: D.

$2x - y = 12$

$x = 5$ and $y = -2$ is the solution of the linear equation $2x - y = 12$
$2x - y = 12$
$LHS = 2x - y$
$2.5 - (-2)$
$10 + 2$
$12$
$RHS = 12$
$LHS = RHS$
It means that $x = 5$ and $y = -2$ is the solution of the linear equation $2x - y = 12.$

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MCQ 681 Mark

The area of the triangle formed by the line $2x + 5y = 10$ and the co-ordinate axis is:

A
$4$ sq. units.
B
$10$ sq. units.
C
$3$ sq. units.
✓
$5$ sq. units.

Answer

Correct option: D.

$5$ sq. units.

To find the area of the triangle formed by the line $2 x+5 y=10$ and co-ordinate axis. We put $x=0$ in given equation at $x=0$, we get $y=2$ at $y=0$ we get $x=5$. So the line cut $y$-axis at 2 and $x$-axis at 5 .
So the height of the triangle is 2 units and the base is 5 units.
Area of triangle $=\frac{1}{2}$ base $\times$ heigh,
$=\frac{1}{2}\times2\times5$
$= 5 sq$. units.

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MCQ 691 Mark

The graph of a linear equation $\text{y}=\frac{9}{5}\text{x}+32$ cuts the $y-$axis at the point:

✓
$(0, 32)$
B
$(-32, 0)$
C
$(0, -32)$
D
$(32, 0)$

Answer

Correct option: A.

$(0, 32)$

When the graph cut at y axis in that case the value of $x-$ coordinate is $0.$
$\text{y}=\frac{9}{5}\text{x}+32$
$\text{y}=\frac{9}{5}.0+\text{32}$
$\text{y}=32$
So, the co-ordinates are $(32, 0)$

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MCQ 701 Mark

Write the correct answer in the following: The graph of the linear equation $y = x$ passes through the point.

A
$\Big(\frac{3}{2},\frac{-3}{2}\Big)$
B
$\Big(0,\frac{3}{2}\Big)$
✓
$(1,1)$
D
$\Big(\frac{-1}{2},\frac{1}{2}\Big)$

Answer

Correct option: C.

$(1,1)$

We know that any point on the line $y = x$ will have $x$ and $y$ coordinates same.So, the graph of the linear equation $y = x$ passes through the point$ (1, 1).$

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MCQ 711 Mark

The graph of the linear equation $2x + 3y = 6$ meets the $y-$axis at the point.

A
$(0, 3)$
B
$(2, 0)$
C
$(3, 0)$
✓
$(0, 2)$

Answer

Correct option: D.

$(0, 2)$

If the graph of the linear equation $2x + 3y = 6$ meets the $y-$axis, then $x = 0.$
Substituting the value of $x = 0$ in equation $2x + 3y = 6,$ we get
$2(0) + 3y = 6$
$\Rightarrow 3y = 6$
$\Rightarrow\text{y}=\frac{6}{3}$
$\Rightarrow y = 2$
So, the point of meeting is $(0, 2).$

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MCQ 721 Mark

If $(4, 19)$ is a solution of the equation $y = ax + 3$, then $a =$

A
$3$
B
$6$
✓
$4$
D
$5$

Answer

Correct option: C.

$4$

Given, $(4, 19)$ is a solution of the equation $y = ax + 3= 19 = 4a + 3$
$= a = 4.$

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MCQ 731 Mark

The graph of the linear equation $y = 3x$ passes through the point.

A
$\Big(0,-\frac{2}{3}\Big)$
B
$\Big(-\frac{2}{3},0\Big)$
C
$\Big(0,\frac{2}{3}\Big)$
✓
$\Big(\frac{2}{3},2\Big)$

Answer

Correct option: D.

$\Big(\frac{2}{3},2\Big)$

$\text{y}=3\text{x}$
$\frac{\text{y}}{3}=\text{x}$
For, $y = 2$, the value of x will be $\frac{2}{3}$
So, $\Big(\frac{2}{3},2\Big)$

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MCQ 741 Mark

The graph of the line $x - y = 0$ passes through the point:

A
$\Big(\frac{-1}{2},\frac{1}{2}\Big)$
B
$\Big(\frac{3}{2},\frac{-3}{2}\Big)$
C
$(0,-1)$
✓
$(1, 1)$

Answer

Correct option: D.

$(1, 1)$

The given linear equation is $x = y = 0.$
We have to check which of the point satisfy the given equation.
consider option (a):
Substituting $\text{x}=-\frac{1}{2}$ and $\text{y}=\frac{1}{2}$ in the $LHS$ if the given linear equation
$\therefore\ \text{x}-\text{y}=-\frac{1}{2}-\frac{1}{2}=-1\neq\text{RHS}$
$\therefore\ \text{x}=-\frac{1}{2}$ and $\text{y}=\frac{1}{2}$ does not satisfy the given linear equation.
Consider option (b):
Substituting $\text{a}=\frac{3}{2}$ and $\text{y}=-\frac{3}{2}$ in the $LHS$ if the given linear equation on
$\therefore\ \text{x}-\text{y}=\frac{3}{2}+\frac{3}{2}=3\neq\text{RHS}$
$\therefore\ \text{x}=-\frac{3}{2}$ and $\text{y}=-\frac{3}{2}$ does not satisfy the given linear eqation on.
Consider option (d):
Substitution $x = 1 $and $y = 1$ in the $LHS$ if the given linear equation
$\therefore\ $$x - y = 1 - 1 = 0 = RHS$
$\therefore\ $$x = 1$ and $y = 1$ satisfies the given linear equation.

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MCQ 751 Mark

The graph of $y = 5$ is a line.

A
Parallel to the $x-$axis at a distance of $6$ units from the origin.
B
Making an intercept $5$ on the $x-$axis.
C
Parallel to the $y-$axis at a distance of $5$ units from the origin.
✓
Making an intercept $5$ on the $y-$axis.

Answer

Correct option: D.

Making an intercept $5$ on the $y-$axis.

As, the graph of $y=5$ is a line parallel to $x$-axis i.e. $y=0$.
$\Rightarrow$ The line represented by the equation $y=5$ is parallel to $x$-axis and intersects $y$-axis at $y=5$. So, the graph of $y=5$ is a line parallel to the $x$-axis at a distance of 5 units from the origin making an intercept 5 on the $y$-axis.

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MCQ 761 Mark

The graph of $x = 3$ is a line:

A
Parallel to $x -$ axis at a distance of $3$ units from the origin.
✓
Parallel to $y -$ axis at a distance of $3$ units from the origin.
C
Makes an intercept $3$ on $x -$ axis.
D
Makes an intercept $3$ on $y -$ axis.

Answer

Correct option: B.

Parallel to $y -$ axis at a distance of $3$ units from the origin.

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MCQ 771 Mark

The point which lies on $x-$axis at a distance of $4$ units in the negative direction of $x-$axis is:

A
$(0, -4)$
B
$(0, 4)$
✓
$(-4, 0)$
D
$(4, 0)$

Answer

Correct option: C.

$(-4, 0)$

At $x$-axis the value of $y$ co-ordinate is $0 x$-axis at a distance of $4$ units in the negative direction so the co-ordinate of $x$-axis is $-4$ . So the co-ordinate of point is $(-4,0)$.

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MCQ 781 Mark

The line represented by the equation $x + y = 16$ passes through $(2, 14).$ How many more lines pass through the point $(2, 14).$

A
$2$
B
$100$
✓
Many
D
$10$

Answer

Correct option: C.

Many

There are many lines pass through the point $(2, 14).$
For example
$x - y = -12$
$2x + y = 18$
And many more.

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MCQ 791 Mark

Which of the following is not a solution of $2x - 3y = 12?$

A
$(6, 0)$
B
$(3, -2)$
C
$(0, -4)$
✓
$(2, 3)$

Answer

Correct option: D.

$(2, 3)$

We have to check $(2,3)$ is a solution of $2 x-3 y=12$ if $(2,3)$ satisfy the equation then $(2,3)$ solution of $2 x-3 y=12$.
$LHS = 2x - 3y$
$2 × 2 - 3 × 3$
$4 - 9 = -5$
$RHS = -5$
$LHS ≠ RHS$
So $(2,3)$ is not a solution of $2 x-3 y=12$.

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MCQ 801 Mark

The linear equation $3x - y = x - 1$ has:

A
No solution
B
Unique solution
C
Two solutions
✓
Infinitely many solutions

Answer

Correct option: D.

Infinitely many solutions

The linear equation $3x - y = x - 1$ has infinitely many solutions.
On simplification, the given equation becomes $2x - y = -1$, which is a single equation with two variables.
Thus, $3x - y = x - 1$ has infinitely many solutions.

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MCQ 811 Mark

The equation of a line parallel to $y-$axis and $4$ units to the right of origin is:

A
$x = -4$
B
$y = -4$
C
$y = 4$
✓
$x = 4$

Answer

Correct option: D.

$x = 4$

The equation of a line parallel to $y$-axis at a distance of $4$ units from it, to its right from the origin.
$x=4$
Because when a line parallel to $y$-axis in that case equation of line is $x=4$. So required equation is $x=4$.

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MCQ 821 Mark

Write the correct answer in the following: Any solution of the linear equation $2x + 0y + 9 = 0$ in two variables is of the form,

✓
$\Big(-\frac{9}{2},\text{m}\Big)$
B
$\Big(\text{n},-\frac{9}{2}\Big)$
C
$\Big(0,-\frac{9}{2}\Big)$
D
$(-9,0)$

Answer

Correct option: A.

$\Big(-\frac{9}{2},\text{m}\Big)$

The given linear equation is
$2x + 0y + 9 = 0$
$\Rightarrow 2x + 9 = 0$
$\Rightarrow 2x = -9$
$\Rightarrow x = -\frac{9}{2}$ and $y$ can be any real number.

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MCQ 831 Mark

Which of the following is a linear equation in two variables?

✓
$2x - 5y = 0$
B
$x + y = 8$
C
$x ^2 = 5x + 3$
D
$5x = y^2 + 3$

Answer

Correct option: A.

$2x - 5y = 0$

In linear equation power of variable $x$ and $y$ should be $1$ and here, the given linear equation has two variable $x$ and $y.$

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MCQ 841 Mark

If we divide both sides of a linear equation with a non-zero number, then the solution of the linear equation.

A
Changes.
✓
Remains the same.
C
None of these.
D
Gets divided by the number.

Answer

Correct option: B.

Remains the same.

If then for any non-zero c.
We can divide both sides of an equation by a non-zero number c, without changing the equation.

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MCQ 851 Mark

The linear equation $3x - 11y = 10$ has:

A
Unique solution
B
Two solutions
✓
Infinitely many solutions
D
No solutions

Answer

Correct option: C.

Infinitely many solutions

$3\text{x}-11\text{y}=10$$\text{y}=\frac{(3\text{x}-10)}{11}$
Now for infinite values of x, y will also have infinite solutions.

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MCQ 861 Mark

$x = 3$ and $y = -2$ is a solution of the equation $4px - 3y = 12$, then the value of $p$ is:

A
$0$
✓
$\frac{1}{2}$
C
$2$
D
$3$

Answer

Correct option: B.

$\frac{1}{2}$

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MCQ 871 Mark

Express $'y'$ in terms of $'x'$ in the equation $5y - 3x - 10 = 0.$

A
$\text{y}=\frac{3-10\text{x}}{5}$
B
$\text{y}=\frac{3+10\text{x}}{5}$
C
$\text{y}=\frac{3\text{x}-10\text{}}{5}$
✓
$\text{y}=\frac{3\text{x}+10}{5}$

Answer

Correct option: D.

$\text{y}=\frac{3\text{x}+10}{5}$

$(D) \text{y}=\frac{3\text{x}+10}{5}$
$5y - 3, x - 10 = 0$
$5y - 3, x = 10$
$5y = 10 + 3x$
$\text{y}=\frac{3\text{x}+10}{5}$

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MCQ 881 Mark

The graph of the linear equation $3x - 5y = 15,$ cuts the $y-$axis at the point:

A
$(2, 0)$
B
$(-2, 0)$
C
$(0, 3)$
✓
$(0, -3)$

Answer

Correct option: D.

$(0, -3)$

The graph of the linear equation $3x - 5y = 15$, cuts the $y-$axis at the point when line cut $y-$axis the co-ordinate of $x$ becomes zero.
So we put $x = 0$ in given equation to find the co-ordinate.
$3x - 5y = 15$
$3(0) - 5y = 15$
$-5y = 15$
$\text{y} = −\frac{15}{5}$
$y = -3$
So the required cordinate is $(0, -3).$

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MCQ 891 Mark

The graph of $x = 3 $is a line:

A
Parallel to the $x -$ axis at a distance of $3$ units from the origin.
✓
Parallel to the $y -$ axis at a distance of $3$ units from the origin.
C
Makes an intercept $3$ on the $x -$ axis.
D
Makes an intercept $3$ on the $y -$ axis.

Answer

Correct option: B.

Parallel to the $y -$ axis at a distance of $3$ units from the origin.

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MCQ 901 Mark

If we multiply both sides of a linear equation with a non-zero number, then the solution of the linear equation:

A
Gets multiplied by the number.
✓
Remains the same.
C
Changes.
D
None of these.

Answer

Correct option: B.

Remains the same.

If for any c. where c is any natural number.
Like addition and subtraction, we can multiply and divide both sides of an equation by a number, c, without changing the equation, where c is any natural number

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MCQ 911 Mark

The linear equation $3x - 5y = 15$ has:

A
Two solutions.
B
A unique solution.
C
No solution.
✓
Infinitely many solutions.

Answer

Correct option: D.

Infinitely many solutions.

Given linear equation: $3x - 5y = 15$
Or, $\text{x}=5\text{y}+\frac{15}{3}$
When $y = 0, x = 153 = 5$
When $y = 3, x = 303 = 10$
When $y = - 3, x = 03 = 0$

$xx$	$5$	$10$	$0$
$yy$	$0$	$3$	$-3$

Plot the points $A(5, 0), B(10, 3)$ and $C(0, -3)$. Join the points and extend them in both the directions.
We get infinite points that satisfy the given equation.
Hence, the linear equation has infinitely many solutions.

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MCQ 921 Mark

$x = 2, y = 5$ is a solution of the linear equation.

A
$x + 2y = 7$
✓
$x + y = 7$
C
$5x + y = 7$
D
$5x + 2y = 7$

Answer

Correct option: B.

$x + y = 7$

$x = 2$ and $y = 5$ satisfy the given equation.

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MCQ 931 Mark

Write the correct answer in the following: Any point on the line $y = x$ is of the form,

✓
$(a, a)$
B
$(0, a)$
C
$(a, 0)$
D
$(a, -a)$

Answer

Correct option: A.

$(a, a)$

Every point on the line $y = x$ has same value of $x-$and $y-$coordinates i.e., $x = a$ and $y = a.$

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MCQ 941 Mark

The equation $x - 2 = 0$ on number line is represented by:

A
Infinitely many lines.
B
A line.
C
Two lines.
✓
A point.

Answer

Correct option: D.

A point.

$x - 2 = 0$
$x = 2$ is a point on the number line.

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MCQ 951 Mark

If the point $(3, 4)$ lies on the graph of $3y = ax + 6$, then the value of $'a'$ is:

A
$0$
✓
$2$
C
$1$
D
$3$

Answer

Correct option: B.

$2$

The point $(3, 4)$ lies on the graph of $3y = ax + 6$So, it will satisfy the equation
$3y = ax + 6$
$3(y) = ax + 6$
$12 = 3a + b$
$12 - 6 = 3a$
$3a = 6$
$\text{a}=\frac{6}{3}$
$\text{a}=2$

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MCQ 961 Mark

The graph of $x = 4$ is a line.

A
Making an intercept $4$ on the $y-$axis.
B
Parallel to the $y-$axis at a distance of $5$ units from the origin.
✓
Making an intercept $4$ on the $x-$axis.
D
Parallel to the $x-$axis at a distance of $4$ units from the origin.

Answer

Correct option: C.

Making an intercept $4$ on the $x-$axis.

As, the graph of $x=4$ is a line parallel to $y$-axis i.e. $x=0$.
$\Rightarrow$ The line represented by the equation $x=4$ is parallel to $y$-axis and intersects $x$-axis at $x=4$.
So, the graph of $x=4$ is parallel to $y$-axis at a distance of 4 units from the origin making an intercept 4 on the $x$-axis.

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MCQ 971 Mark

If we multiply or divide both sides of a linear equation with a non-zero number, then the solution of the linear equation:

A
Changes.
✓
Remains the same.
C
Only changes in case of multiplication.
D
Only changes in case of division.

Answer

Correct option: B.

Remains the same.

If we multiply or divide both sides of a linear equation with a non-zero number, then the solution of the linear equation remains the same.

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MCQ 981 Mark

The point of the form $(-a, a)$, where a lies on

✓
The line$ x + y = 02$
B
The $y-$axis
C
The $x-$axis
D
The line $y = x$

Answer

Correct option: A.

The line$ x + y = 02$

The point $(a,-a)$ lies on line $x+y=0$
Here is the verification
Put $x=a$ in equation
$x + y = 0$
$a + y = 0$
$y = -a$
Hence it is prove that $(a,-a)$ is a solution of $x+y=0$

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MCQ 991 Mark

If $x$ and $y$ are both positive solutions of equation $ax + by + c = 0$, always lie in the:

✓
First quadrant
B
Second quadrant
C
Third quadrant
D
Fourth quadrant

Answer

Correct option: A.

First quadrant

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MCQ 1001 Mark

The linear equation $3x - 11y = 10$ has:

A
Unique solution
B
Two solution
✓
Infinitely many solutions
D
No solution

Answer

Correct option: C.

Infinitely many solutions

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Maths M.C.Q