Questions · Page 2 of 4

M.C.Q (1 Marks)

MCQ 511 Mark
Which of the following forms $\ce{M_2O}$ type of oxide?
  • A
    $Al$
  • B
    $B$
  • $Tl$
  • D
    $Ca$
Answer
Correct option: C.
$Tl$
$Tl^+ ($due to inert pair effect$)$ is stable and forms compounds like $\ce{Tl_2​O}$.
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MCQ 521 Mark
What is the hybridisation of $C-$atom in $\ce{CO_2}$ molecule?
  • A
    $Sp ^2$
  • $Sp$
  • C
    $S p^3$
  • D
    None of these.
Answer
Correct option: B.
$Sp$
${ \ \ \ \ \sigma\ \ \ \ \ \ \ \sigma}\\\text{O}=\text{C}=\text{O}: sp -$ hybridisation. $(\because2\sigma$ bonds$)$
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MCQ 531 Mark
Which one of the following is paramagnetic in nature?
  • $NO$
  • B
    $\mathrm{N}_2 \mathrm{O}$
  • C
    $\mathrm{N}_2 \mathrm{O}_5$​
  • D
    All of the above
Answer
Correct option: A.
$NO$
Whenever two electrons are paired together in an orbital, or their total spin is $0$, they are diamagnetic electrons. Atoms with all diamagnetic electrons are called diamagnetic atoms.
A paramagnetic electron is an unpaired electron. $NO$ has one unpaired electron. Hence, it is paramagnetic in nature.
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MCQ 541 Mark
Which of the following compounds have zero dipole moment ?
  • $\mathrm{BF}_3$
  • B
    $\mathrm{SnCl}_2$
  • C
    $\mathrm{H}_2 \mathrm{O}$
  • D
    $\mathrm{NH}_3$​
Answer
Correct option: A.
$\mathrm{BF}_3$
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MCQ 551 Mark
Which among the following substances is not a component of the mixture used for glazing pottery?
  • Feldspar
  • B
    Silica
  • C
    Borax
  • D
    Alumina
Answer
Correct option: A.
Feldspar
Ceramic glaze is an impervious layer or coating of a vitreous substance which has been fused to a ceramic body through firing. Glaze can serve to colour, decorate or waterproof an item.
Pottery glaze is made up of five basic components. These components are silica, alumina, flux, colourants and modifiers.
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MCQ 561 Mark
An aqueous solution of borax is:
  • A
    Neutral.
  • B
    Amphoteric.
  • Basic.
  • D
    Acidic.
Answer
Correct option: C.
Basic.
Borax is a salt of a strong base $\ce{(NaOH)}$ and a weak acid $(\mathrm{H}_3 \mathrm{BO}_3).$ It is, therefore, basic in nature.
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MCQ 571 Mark
Which of the following is used for making optical instruments:
  • $\ce{SiO_2}$​
  • B
    $Si$
  • C
    $\ce{SiH_4}$​
  • D
    $\ce{SiC}$
Answer
Correct option: A.
$\ce{SiO_2}$​
Silica is an important ingredient in making glass, which is extensively used in making optical devices.
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MCQ 581 Mark
On commercial scale $CO$ is prepared by passage of steam over:
  • Hot coke.
  • B
    Coal.
  • C
    Diamond.
  • D
    Graphite.
Answer
Correct option: A.
Hot coke.
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MCQ 591 Mark
Which of the following oxides dissolves in both hydrochloric acid and sodium hydroxide solution? $(1993)$
  • A
    $Na$
  • B
    $\ce{MgO}$
  • C
    $\ce{BaO}$
  • $\mathrm{Al}_2 \mathrm{O}_3$​
Answer
Correct option: D.
$\mathrm{Al}_2 \mathrm{O}_3$​
$\mathrm{Al}_2 \mathrm{O}_3$​ is an amphoteric oxide.
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MCQ 601 Mark
Borax bead test is used to identify the:
  • A
    Anion in coloured salt
  • Cation in coloured salt
  • C
    Anion in white salt
  • D
    Cation in white salt
Answer
Correct option: B.
Cation in coloured salt
Borax bead test is used to identify the coloured metal ions in given salt. The coloured metal ions form their corresponding metaborate with boron and their colour used to identify them.
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MCQ 611 Mark
$Ti^+$ is more stable than $TI^{3+}$ due to:
  • Inert pair effect.
  • B
    Smaller size.
  • C
    Bigger size.
  • D
    Higher hydration energy.
Answer
Correct option: A.
Inert pair effect.
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MCQ 621 Mark
Which of the following reacts with nitrogen when heated in air:
  • $Al$
  • B
    $C$
  • C
    $Na$
  • D
    $K$
Answer
Correct option: A.
$Al$
$\ce{2Al + N_2 ​\rightarrow 2AlN}$
Thus, $Al$ reacts with nitrogen when heated in air to form aluminium trinitride.
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MCQ 631 Mark
Electronic configuration of only one $p-$block element is exceptional. One molecule of that element consists of how many atoms of it?
  • One
  • B
    Two
  • C
    Three
  • D
    Four
Answer
Correct option: A.
One
The electronic configuration of an only $p-$block element is exceptional. One molecule of that element consists of only one atom of it.
As the exception is found in only He, as helium has the electronic configuration to be $1s^2$. But other member of the same group has $\ce{ns^2np^6}$ configuration.
So, this is an exceptional case where He does not resemble its group in its configuration.
And as He is a noble gas element so it is monoatomic gas.
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MCQ 641 Mark
Which of the following metal forms a protective oxide layer to prevent corrosion?
  • A
    $Cu$
  • B
    $Mg$
  • $Al$
  • D
    $Mn$
Answer
Correct option: C.
$Al$
$\mathrm{Al}_2 \mathrm{O}_3$​ is formed which forms a protective layer on the metal.
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MCQ 651 Mark
Which of the following oxides is acidic in nature?
  • $ \mathrm{B}_2 \mathrm{O}_3 $
  • B
    $ \mathrm{Al}_2 \mathrm{O}_3$
  • C
    $ \mathrm{Ga}_2 \mathrm{O}_3 $
  • D
    $ \mathrm{In}_2 \mathrm{O}_3 $
Answer
Correct option: A.
$ \mathrm{B}_2 \mathrm{O}_3 $
$ \mathrm{B}_2 \mathrm{O}_3 $ is acidic in nature. It reacts with basic oxides to form metal borates. Acidic nature decreases on moving down the group.
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MCQ 661 Mark
Graphite conducts electricity due to the:
  • Highly delocalised nature of $t-$electrons.
  • B
    Highly localised nature of $tt-$electrons.
  • C
    Highly polarised nature of $tt-$electrons.
  • D
    None of the above.
Answer
Correct option: A.
Highly delocalised nature of $t-$electrons.
Graphite conducts electricity due to the highly delocalised nature of $\pi -$electrons.
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MCQ 671 Mark
The hydrides of the first elements in groups $15 - 17$, namely $\ce{NH3​,H2​O}$ and $HF$ respectively, show abnormally high values for melting and boiling points. This is due to:
  • A
    Small size of $N, O$ and $F$
  • The ability to form extensive intermolecular $H-$bonding
  • C
    The ability to form extensive intramolecular $H-$bonding
  • D
    Effective van der Waal's interaction
Answer
Correct option: B.
The ability to form extensive intermolecular $H-$bonding
The hydrides of the first elements in groups $15 - 17$, namely $\ce{NH_3​, H_2​O}$ and $HF$ respectively, show abnormally high values for melting and boiling points. This is due to the ability to form extensive inter$-$molecular $H-$bonding. In these hydrides, $H$ atom is attached to highly electronegative $N, O$ or $F$ atoms resulting in stronger hydrogen bonds which lead to molecular associations. Large amount of energy is needed to break these hydrogen bonds.
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MCQ 681 Mark
Which element has the highest valency with respect to oxygen?
  • A
    Sodium
  • B
    Aluminium
  • Chlorine
  • D
    Sulphur
Answer
Correct option: C.
Chlorine
The valence of an element with respect to oxygen is twice the number of oxygen atoms with which one atom of that element chemically combines.
The valency of chlorine with respect to oxygen is $7$.
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MCQ 691 Mark
Elements of group $14$ used in semiconductors are:
  • A
    $\text{C, Si, Ge}$
  • B
    $\text{Si, Ge, Sn}$
  • $\text{Si, Ge}$
  • D
    $\text{B, Si, Ge}$
Answer
Correct option: C.
$\text{Si, Ge}$
Silicon is found in the basis of all electronic devices. It is a semiconductor.
Germanium is another element used in semiconductors.
Ultrapure form of $Ge$ and $Si$ are used to make translators and semi conductors.
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MCQ 701 Mark
Cement, the important building material is a mixture of oxides of several elements. Besides calcium, iron and sulphur, oxides of elements of which of the group $(s)$ are present in the mixture?
  • A
    group $2$.
  • groups $2, 13$ and $14$.
  • C
    groups $2$ and $13.$
  • D
    groups $2$ and $14.$
Answer
Correct option: B.
groups $2, 13$ and $14$.
Cement is manufactured by combining substances which are lime$\text{(CaO)}$, clay contains silica $\text{(SiO)}$ and oxides of $Al, Mg$ and iron.
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MCQ 711 Mark
Which of the following oxidation states are the most characteristic for lead and tin?
  • A
    $+2,+2$
  • B
    $+4,+2$
  • $+2,+4$
  • D
    $+4,+4$
Answer
Correct option: C.
$+2,+4$
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MCQ 721 Mark
Reaction of ammonia with diborane gives initially $\mathrm{B}_2 \mathrm{H}_6 \cdot 2 \mathrm{NH}_3$ which on further heating gives:
  • Borazine.
  • B
    Borax.
  • C
    Boric acid.
  • D
    All of these.
Answer
Correct option: A.
Borazine.
Reaction of ammonia with diborane gives initially $\mathrm{B}_2 \mathrm{H}_6 \cdot 2 \mathrm{NH}_3$ which is formulated as $\left[\mathrm{BH}_2\left(\mathrm{NH}_3\right)_2\right]^{+}$. $\left[\mathrm{BH}_4\right]^{-}$further heating gives borazine, $\mathrm{B}_3 \mathrm{N}_3 \mathrm{H}_6$ known as "inorganic benzene" in view of its ring structure with alternate $BH$ and $NH$ groups.
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MCQ 731 Mark
Which element froms maximum compound in chemistry?
  • A
    $O$
  • B
    $H$
  • C
    $Si$
  • $C$
Answer
Correct option: D.
$C$
Carbon is the element which forms the highest number of compounds especially organic compounds due to its catenation $($long chain formation$)$ ability. Carbon, with $4$ valence atoms and by virtue of being small in size is most suited to form the highest number of compounds.
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MCQ 741 Mark
Which of the following is wrong about silica?
  • A
    Purest form of silica is know as quartz.
  • B
    Quartz is also know as rock crystal.
  • C
    Quartz contain hexagonal prisms.
  • $U.V$. light cannot pass through quartz.
Answer
Correct option: D.
$U.V$. light cannot pass through quartz.
Quartz is the second most abundant mineral in the Earth's continental crust, after feldspar. Its crystal structure is a continuous framework of $\ce{SiO_4}$ silicon$–$oxygen tetrahedral, with each oxygen being shared between two tetrahedra, giving an overall chemical formula of $\ce{SiO_2}$. Pure quartz, traditionally called rock crystal or clear quartz, is colorless and transparent or translucent, $U.V$. light can pass through quartz.
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MCQ 751 Mark
All group$-14$ members when heated in oxygen form:
  • A
    Monoxide.
  • B
    Dioxide.
  • C
    Trioxide.
  • Monoxide and dioxide both.
Answer
Correct option: D.
Monoxide and dioxide both.
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MCQ 761 Mark
Among $\ce{III-A}$ group elements, the elements with highest and lowest $I.P$. values are:
  • A
    $B, Tl$
  • $B, In$
  • C
    $B, Al$
  • D
    $B, Ga$
Answer
Correct option: B.
$B, In$
$I.P$. does not smoothly decrease down in $\text{III−A}$ group. The decrease from $B$ to $Al$ is associated with increase in size. The observed discontinuity in the $I.P.$ values between $Al$ and $Ga$, and between In and $Tl$ are due to the inability of $d-$ and $f-$electrons, which have low screening effect to compensate the increase in nuclear charge.
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MCQ 771 Mark
In the electrothermal process, the compound displaced by silica from calcium phosphate is:
  • A
    Calcium
  • B
    Phosphine
  • C
    Phosphorus
  • Phosphorus pentoxide
Answer
Correct option: D.
Phosphorus pentoxide
In the electrothermal process, the compound displaced by silica from calcium phosphate is phosphorus pentoxide. It is then reduced by coke in electric furnace to get white phosphorus.
$\mathrm{Ca}_3\left(\mathrm{PO}_4\right)_2+{ }_3 \mathrm{SiO}_2 \rightarrow{ }_3 \mathrm{CaSiO}_3+\mathrm{P}_2 \mathrm{O}_5$​
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MCQ 781 Mark
Anhydrous borax is:
  • $ \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 $
  • B
    $\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 5 \mathrm{H}_2 \mathrm{O} $
  • C
    $ \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O} $
  • D
    $ \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 8 \mathrm{H}_2 \mathrm{O} $
Answer
Correct option: A.
$ \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 $
Anhydrous borax has formula $ \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 $​.
Anhydrous means no water of crystallisation.
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MCQ 791 Mark
For which of the following reactions, is Gay Lussac's law not applicable?
  • A
    Formation of HI from its constituents
  • B
    Formation of $\mathrm{NH}_3$ from its constituents
  • Formation of $\mathrm{CO}_2$ from its constituents
  • D
    Formation of $\mathrm{SO}_3$ from $\mathrm{SO}_2$ and $\mathrm{O}_2$​
Answer
Correct option: C.
Formation of $\mathrm{CO}_2$ from its constituents
Gay Lussac's law not applicable to formation of $\ce{CO_2}$​ from its constituents as carbon and oxygen exist in different physical states.
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MCQ 801 Mark
The structure of silicon$(IV)$ oxide belongs to the type:
  • A
    Ionic lattice
  • B
    Macromolecular, with a layer structure
  • C
    Molecular lattice, with van der Waals forces among the molecules
  • Macromolecular, with a non$-$layer structure
Answer
Correct option: D.
Macromolecular, with a non$-$layer structure
$\text{Si(IV)}$ oxide is macromolecular with a non layer structure similar to diamond.
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MCQ 811 Mark
Stannite is an ore of $.........$
  • Tin
  • B
    Lead
  • C
    Germanium
  • D
    Carbon
Answer
Correct option: A.
Tin
Stannite is a mineral, a sulfide of copper, iron, and tin. The chemical formula $\mathrm{Cu}_2 \mathrm{FeSnS}_4$.​
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MCQ 821 Mark
Which of the following property does not support anamolous behaviour of boron?
  • A
    Small size
  • B
    High electronegativity
  • C
    High ionization energy
  • Formation of trihalides
Answer
Correct option: D.
Formation of trihalides
Formation of trihalides does not support anomalous behaviour of boron as other elements of boron family also form trihalides such as $\ce{AlCl_3}$​.
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MCQ 831 Mark
Which of the following is most metallic:
  • A
    $B$
  • B
    $Al$
  • C
    $Mg$
  • $K$
Answer
Correct option: D.
$K$
$K$ is most metallic due to lowest ionisation enthalpy.
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MCQ 841 Mark
Borax bead test is responded by:
  • A
    Divalent metals
  • B
    Heavy metals
  • C
    Light metal
  • Metals which form coloured metaborates
Answer
Correct option: D.
Metals which form coloured metaborates
When the glossy bead is dipped in metal oxide and heated, the corresponding metal metaborates are formed.
The characteristic colour of these metaborates enables us to identify the metal.
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MCQ 851 Mark
Glass reacts with $HF$ forming :
  • A
    $\mathrm{F}_2$
  • $\mathrm{H}_2 \mathrm{SiF}_6$
  • C
    $\mathrm{CaF}_2$
  • D
    $\ce{NaF}$
Answer
Correct option: B.
$\mathrm{H}_2 \mathrm{SiF}_6$
$\mathrm{SiO}_2+6 \mathrm{HF} \rightarrow \mathrm{H}_2 \mathrm{SiF}_6+2 \mathrm{H}_2 \mathrm{O}$
When glass reacts with $HF, \mathrm{H}_2 \mathrm{SiF}_6$​ is formed.
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MCQ 861 Mark
$\mathrm{SnCl}_2$ is good:
  • Reducing agent.
  • B
    Oxidising agent.
  • C
    Bleaching agent.
  • D
    Dehydrating agent.
Answer
Correct option: A.
Reducing agent.
$\text{SnCl}_2+\text{2FeCl}_3\xrightarrow{\ \ \ \ \ \ \ \ }2\text{FeCl}_2+\text{SnCl}_4$
$\mathrm{SnCl}_2$ is good reducing agent.
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MCQ 871 Mark
In which of the following the inert pair effect is most prominent ?
  • A
    $C$
  • B
    $Ge$
  • C
    $Si$
  • $Pb$
Answer
Correct option: D.
$Pb$
Due to poor or ineffective shielding of the $ns^2$ electrons of the valence shell by intervening d$-$ and f$-$electrons, the $s-$electrons are reluctant to participate in bond formation.
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MCQ 881 Mark
$\ce{CO_2}$ is gas, while $\ce{SiO_2}$ is solid because:
  • A
    $\mathrm{CO}_2$ is a linear molecule, while $\mathrm{SiO}_2$ is angular.
  • B
    van der Waals' forces are very strong in $\mathrm{SiO}_2$.
  • C
    $\mathrm{CO}_2$ is covalent, while $\mathrm{SiO}_2$ is ionic.
  • $Si$ cannot form stable bonds with $O$, hence $Si$ has to form a $3D$ lattice.
Answer
Correct option: D.
$Si$ cannot form stable bonds with $O$, hence $Si$ has to form a $3D$ lattice.
$\ce{SiO_2}$ is solid because $Si$ cannot form stable bonds with $O$, hence $Si$ has to form a $3D$ lattice of $\ce{SiO_2}$ molecules and form solid structure.
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MCQ 891 Mark
Which of the following is$/$are allotrope$(s)$ of carbon?
  • A
    Diamond.
  • B
    Graphite.
  • C
    Fullerene.
  • All of these.
Answer
Correct option: D.
All of these.
Diamond, graphite and fullerene are the allotropes of carbon.
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MCQ 901 Mark
A compound $X$, of boron reacts with $\ce{NH_3}$ on heating to give another compound $Y$ which is called inorganic benzene. The compound $X$ can be prepared by treating $\ce{BF_3}$ with Lithium aluminium hydride. The compounds $X$ and $Y$ are represented by the formulas.
  • $ \mathrm{B}_2 \mathrm{H}_6, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 $
  • B
    $ \mathrm{~B}_2 \mathrm{O}_3, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 $
  • C
    $ \mathrm{BF}_3, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 $
  • D
    $ \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6, \mathrm{~B}_2 \mathrm{H}_6 $
Answer
Correct option: A.
$ \mathrm{B}_2 \mathrm{H}_6, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 $
A compound $X$, of boron reacts with $NH_3$ on heating to give another compound $Y$ which is called inorganic benzene.
$ \ \ \ \ \ \ 3\text{B}_2\text{H}_6+6\text{NH}_3\rightarrow3[\text{BH}_2(\text{NH}_3)_2]^+[\text{BH}^4]^-\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{(x)} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow \text{heat}\\ \ \ \ \ \ \ \ \ ^\text{Diborane}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2\text{B}_3\text{N}_3\text{H}_6+12\text{H}_2 \\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(Y)}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Borazole/ Inorganic benzene}\\4\text{BF}_3+3\text{LiAlH}_4\xrightarrow{ \ \ \ \ \ \ \ \ \ }2\text{B}_2\text{H}_6+3\text{LiF}+3\text{AIF}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(x)}$
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MCQ 911 Mark
The most abundant $\text{IVA}$ group elements in the earth's crust is:
  • Germanium
  • B
    Carbon
  • C
    Silicon
  • D
    Tin
Answer
Correct option: A.
Germanium
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MCQ 921 Mark
Which of the following member of the carbon family does not have an allotrope?
  • A
    $Si$
  • B
    $Sn$
  • C
    $C$
  • $Ge$
Answer
Correct option: D.
$Ge$
In carbon family only carbon, silicon and tin forms allotrope. Carbon has multiple allotrope, Silicon has two known allotropes that exist at room temperature and Tin also has two allotropes.Ge does not have an allotrope.
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MCQ 931 Mark
Percentage of lead in lead pencil is:
  • $0$
  • B
    $20$
  • C
    $80$
  • D
    $60$
Answer
Correct option: A.
$0$
It is made up of graphite
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MCQ 941 Mark
Borax is used as cleansing agent because on dissolving in water it forms:
  • Alkaline solution.
  • B
    Acidic solution.
  • C
    Bleaching solution.
  • D
    Colloidal solution.
Answer
Correct option: A.
Alkaline solution.
$\text{Na}_2\text{B}_4\text{O}_7:10\text{H}_2\text{O}+6\text{H}_2\text{O}\rightarrow\\2\text{NaOH}+4\text{H}_3\text{BO}_3+10\text{H}_2\text{O}\\\ \ ^\text{(Strong)}\ \ \ \ \ \ \ ^\text{(Weak)}$
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MCQ 951 Mark
Dry ice is:
  • A
    Solid $\mathrm{NH}_3$.
  • B
    Solid $\mathrm{SO}_2$.
  • Solid $\mathrm{CO}_2$.
  • D
    Solid $\mathrm{N}_2$.
Answer
Correct option: C.
Solid $\mathrm{CO}_2$.
Solid $\mathrm{CO}_2$ is called dry ice becaouse it is used for making ice bath for organic reaction in laboratory. It is prepared by cooling $\mathrm{CO}_2$ gas at high pressure.
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MCQ 961 Mark
The tendency to behave as Lewis acid decreases as the size:
  • Increases.
  • B
    Decreases.
  • C
    Remains same.
  • D
    First increases then decreases.
Answer
Correct option: A.
Increases.
The tendency to behave as a Lewis acid decreases with the increase in the size on moving down the group.
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MCQ 971 Mark
Xenon hexafluoride reacts with silica to form a xenon compound $X$. The oxidation state of $Xe$ in $X$ is :
  • A
    $+2$
  • B
    $+4$
  • $+6$
  • D
    $0$
Answer
Correct option: C.
$+6$
$\mathrm{SiO}_2+2 \mathrm{XeF}_6 \rightarrow 2 \mathrm{XeOF}_4+\mathrm{SiF}_4$​
Oxidation state of $Xe$ in $(X)$ is $+ 6$
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MCQ 981 Mark
Boric acid is not a protonic acid but it acts as a Lewis acid by:
  • Accepting electrons from a hydroxyl ion.
  • B
    Donating electrons to a chloride ion.
  • C
    Donating electrons to a proton.
  • D
    Accepting proton from water.
Answer
Correct option: A.
Accepting electrons from a hydroxyl ion.
Boric acid is not a protonic acid, but it acts as a Lewis acid by accepting electrons from a hydroxyl ion.
$\text{B(OH)}_3+2\text{HOH}\xrightarrow{\ \ \ \ \ \ \ }[\text{B}(\text{OH})_4]^-+\text{H}_3\text{O}^+$.
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MCQ 991 Mark
Which statement is correct with respect to the property of the elements with increase in atomic number in the carbon family?
  • A
    Their metallic character decreases
  • The stability of $+2$ oxidation state increases
  • C
    Their ionization energy increases
  • D
    Their atomic size decreases
Answer
Correct option: B.
The stability of $+2$ oxidation state increases
Due to the inert pair effect, as we move down the group, lower oxidation state becomes more stable, so stability of $2+$ oxidation state increases.
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MCQ 1001 Mark
Which of the following elements has a limited co$-$ordination number of four?
  • A
    $Sn$
  • $C$
  • C
    $Si$
  • D
    $Ge$
Answer
Correct option: B.
$C$
Tin, silicon and germanium can extend their valency owing to the empty $d$ orbitals present in their configuration. However, Carbon cannot do so.
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M.C.Q (1 Marks) - Page 2 - Chemistry STD 11 Science Questions - Vidyadip