Triangles ABC and DEF are similar.
If AC = 19 cm and DF = 8 cm, find the ratio between the areas of two triangles.
If AC = 19 cm and DF = 8 cm, find the ratio between the areas of two triangles.
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Similarity questions
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In the adjoining figure, $\triangle ACB \sim \triangle APQ.$ If $BC = 10 cm, PQ = 5 cm, BA = 6.5 cm$ and $AP = 2.8 cm$ find the area $(\triangle ACB):$ area $(\triangle APQ).$
View full solution →Triangles ABC and DEF are similar.
If AC = 19 cm and DF = 8 cm, find the ratio between the area of two triangles.
If AC = 19 cm and DF = 8 cm, find the ratio between the area of two triangles.
In the adjoining figure, the medians BD and CE of a ∆ABC meet at G. Prove that
(i) ∆EGD ∼ ∆CGB and
(ii) BG = 2GD for (i) above.
(i) ∆EGD ∼ ∆CGB and
(ii) BG = 2GD for (i) above.
In ΔPQR, L and M are two points on the base QR, such that ∠LPQ = ∠QRP and ∠RPM = ∠RQP.
Prove that : (i) ΔPQL ∼ ΔRPM
(ii) QL. Rm = PL. PM
(iii) $PQ^2 = QR. QL$.
View full solution →Prove that : (i) ΔPQL ∼ ΔRPM
(ii) QL. Rm = PL. PM
(iii) $PQ^2 = QR. QL$.
Triangles ABC and DEF are similar.
If area $(\triangle ABC) = 9 cm^2$, area ($\triangle$ DEF) = $64 cm^2$ and $BC = 5.1$ cm find AB.
View full solution →If area $(\triangle ABC) = 9 cm^2$, area ($\triangle$ DEF) = $64 cm^2$ and $BC = 5.1$ cm find AB.
Triangles $ABC$ and $DEF$ are similar.
If area $(\triangle ABC) = 16 cm^2$, area $(\triangle DEF) = 25 cm^2$ and $BC = 2.3 cm$ find $EF.$
View full solution →If area $(\triangle ABC) = 16 cm^2$, area $(\triangle DEF) = 25 cm^2$ and $BC = 2.3 cm$ find $EF.$
In fig. ABCD is a trapezium in which AB | | DC and AB = 2DC. Determine the ratio between the areas of ΔAOB and ΔCOD.
In figure ABC and DBC are two triangles on the same base BC. Prove that
$\frac{\text { Area }(\triangle ABC )}{\text { Area }(\triangle DBC )}=\frac{ AO }{ DO }$.
View full solution →$\frac{\text { Area }(\triangle ABC )}{\text { Area }(\triangle DBC )}=\frac{ AO }{ DO }$.
Prove that the area of the triangle BCE described on one side BC of a square ABCD as base is one half of the area of similar triangle ACF described on the diagonal AC as base.
On a map drawn to a scale of $1: 2,50,000$, a triangular plot of land has the following measurements, $AB =3 cm, BC =$ $4 cm, \angle ABC =90^{\circ}$. Calculate:
(i) The actual length of $A B$ in Kms .
(ii) The area of Plot in sq. kms.
View full solution →(i) The actual length of $A B$ in Kms .
(ii) The area of Plot in sq. kms.
On a map drawn to scale of $1: 2,50,000$ a rectangular plot of land $A B C D$ has the following measurement $A B=12 cm$, $B C=16 cm$ angles $A, B, C$, and $D$ are $90^{\circ}$ each. Calculate:
(i) The diagonal distance of the plot of land in
(ii) Actual length of diagonal.
View full solution →(i) The diagonal distance of the plot of land in
(ii) Actual length of diagonal.
In the adjoining figure $\text{ABC}$ is a right angle triangle with $\angle B A C=90^{\circ}$, and $A D \perp B C$.
$(i)$ Prove $\triangle ADB \sim \triangle CDA$.
$(ii)$ If $BD =18 \ cm, C D=8 \ cm$ find $AD$ .
$(iii)$ Find the ratio of the area of $\triangle A D B$ is to area of $\triangle C D A$.
View full solution →$(i)$ Prove $\triangle ADB \sim \triangle CDA$.
$(ii)$ If $BD =18 \ cm, C D=8 \ cm$ find $AD$ .
$(iii)$ Find the ratio of the area of $\triangle A D B$ is to area of $\triangle C D A$.
D and E are points on the sides AB and AC respectively of a Δ ABC such that DE | | BC and divides Δ ABC into two parts, equal in area. Find $\frac{ BD }{ AB }$.
View full solution →Equilateral triangles are drawn on the sides of a right angled triangle. Show that the area of the triangle on the hypotenuse is equal to the sum of the areas of triangles on the other two sides.
In Δ ABC, ∠ABC = ∠DAC. AB = 8 cm, AC = 4 cm, AD = 5 cm.
1) Prove that ΔACD is similar to ΔBCA.
2) Find BC and CD
3) Find area of ΔACD: area of ΔBCA
1) Prove that ΔACD is similar to ΔBCA.
2) Find BC and CD
3) Find area of ΔACD: area of ΔBCA
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