$\frac{1+\tan^2\text{A}}{1+\cot^2\text{A}}$ is equal to:
- A$\sec^2\text{A}$
- B$-1$
- C$\cot^2\text{A}$
- ✓$\tan^2\text{A}$
Answer: D.
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Answer: D.
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