- ✓$x=\frac{-m}{2}+\frac{m}{\sqrt{2}} \cos \theta_i y=\frac{-m}{2}+\frac{m}{\sqrt{2}} \sin \theta$
- B$x=\frac{-m}{2}+\frac{m}{\sqrt{2}} \cos \theta_2 y=\frac{+m}{2}+\frac{m}{\sqrt{2}} \sin \theta$
- Cx = 0, y = 0
- Dx = m cos θ, y = m sin θ
Answer: A.
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