The binding energy of a satellite revolving around planet in a circular orbit is $3 \times 109 J$. Its kinetic energy is _________
- A$6 \times 10^9 J$
- B$-3 \times 10^9 J$
- C$-6 \times 10^{+9} J$
- ✓$3 \times 10^{+9} J$
Answer: D.
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