Question 11 Mark
$\int_0^1 \frac{d x}{1+x^2}$ का मान ज्ञात कीजिए।
Answer
View full question & answer→$\int_0^1 \frac{d x}{1+x^2}=\left[\tan ^{-1} x\right]_0^1$
$=\tan ^{-1} 1-\tan ^{-1} 0=\frac{\pi}{4}-0=\frac{\pi}{4}$
$=\tan ^{-1} 1-\tan ^{-1} 0=\frac{\pi}{4}-0=\frac{\pi}{4}$