Question
$\int_0^1 \frac{d x}{1+x^2}$ का मान ज्ञात कीजिए।

Answer

$\int_0^1 \frac{d x}{1+x^2}=\left[\tan ^{-1} x\right]_0^1$
$=\tan ^{-1} 1-\tan ^{-1} 0=\frac{\pi}{4}-0=\frac{\pi}{4}$ 

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