Questions · Page 4 of 4

M.C.Q (1 Marks)

Question 1511 Mark
Monica wanted to take photographs of a monument. But since the surrounding is filled with smoke, she is not able to take good photos. Which one of the following electromagnetic waves can be used in this situation to help Monica?
Answer
  1. Infrared waves
Explanation:
Infrared waves can be used to take photographs during conditions of smoke, fog, etc. as these waves are scattered less than visible rays and hence travel longer distances through the atmosphere. So, using infrared waves can help Monica out.
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Question 1521 Mark
Is the ratio of frequencies of UV rays and IR rays in the glass more than, less than or equal to 1?
Answer
  1. More than 1
Explanation:
The ratio of frequencies of UV rays and IR rays in the glass is more than 1. This is because the frequency of UV rays is greater than that of infrared rays. This situation is applicable in glass or vacuum or air.
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Question 1531 Mark
The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum is $B_{0​ }= 510nT.$ The amplitude of the electric field part of the wave is:
Answer
Given,
$B_0​ = 510nT$
$c = 3\times 10^8\ m/s$
The magnitude of electric field is given by
$E_0​ = B_{0​}c$
$E_0​ = 510\times 10^{−9}\times 3\times 10^8$
$E_{0 }​= 153 N C^{−1}$
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Question 1541 Mark
In an electromagnetic wave.
Answer
  1. Power is transmitted in a direction perpendicular to both the field
Explanation:
For electromagnetic waves E and B are always perpendicular to each other and perpendicular to the direction of propagation. The direction of propagation is the direction of E × B.
The direction of propagation of the wave is the direction of propagation of its energy and power.
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Question 1561 Mark
An $EM$ wave radiates outwards from a dipole antenna, with $E_0$ as the amplitude of its electric field vector. The electric field $E_0$ which transports significant energy from the source falls off as$:$
Answer
A diode antenna radiates the electromagnetic waves outwards. The amplitude of electric field vector $(E_0)$ which transports significant energy from the source falls intensity inversely as the distance $(r)$ from the antenna,
i.e., $\text{E}_0\propto\frac{1}{\text{r}}$.
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Question 1571 Mark
In Thomson's experiment to measure e/ m of electron, the electric and the magnetic fields are.
Answer
  1. Perpendicular to each other
Explanation:
The experimental set up of Thomson's experiment is shown in figure, 
According to this figure, the electric field is applied between two horizontal parallel plates, this field is directed in downward direction.
The cross in figure shows the magnetic field is directed inside the paper. Therefore, both the fields are perpendicular to each other.
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Question 1581 Mark
What is the ratio of the speed of infrared and ultraviolet rays in a vacuum?
Answer
  1. 1
Explanation:
 Ratio = 1 because the speed of an electromagnetic wave in vacuum is independent of its wavelength or frequency. Therefore, the ratio of speed of infrared and ultraviolet rays in a vacuum is one.
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Question 1591 Mark
Which of the following statement(s) is/ are correct?
Answer
  1. Conduction current obeys Ohm's law whereas displacement current does not.
Explanation:
Displacement current is the current that occurs due to charging electric field  introduced by maxwell. It depends on the frequency of electric field while conduction current follows ohms law, requires medium displacement.Current doesnot follow ohms law nor require medium.
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Question 1601 Mark
Instantaneous displacement current 1A in the space between the parallel plates of $1\mu\text{F}$ capacitor can be established by changing the potential difference at the rate of:
Answer
  1. $\frac{10^6\text{V}}{\text{s}}$
Explanation:
In a capacitor of capacitance C,
$\text{V}=\frac{\text{q}}{\text{C}}$
$\Rightarrow\frac{\text{dV}}{\text{dt}}=\frac{\text{i}}{\text{C}}=\frac{1\text{A}}{1\mu\text{F}}=\frac{10^6\text{V}}{\text{s}}$
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Question 1611 Mark
One requires $11\ eV$ of energy to dissociate a carbon monoxide molecule into carbon and oxygen atoms. The minimum frequency of the appropriate electromagnetic radiation to achieve the dissociation lies in:
Answer
Here it is given, the energy required to dissociate a carbon monoxide molecule into catbon and oxygon atoms is $E = 11\ eV$
We know that$, E = hf = 6.62 \times 10^{-34}J-s$
$f =$ frequency
$\Rightarrow 11\ eV = hf$
$\text{f}=\frac{11\times1.6\times10^{-19}}{6.62\times10^{-34}}=2.65\times10^{15}\text{Hz}$
This frequency radiation belongs to ultraviolet region.
Important point:
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Question 1621 Mark
Which of the following waves have a maximum frequency?
Answer
  1. Gamma rays
Explanation:
Gamma rays have a maximum frequency.
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Question 1631 Mark
A free electron is placed in the path of a plane electromagnetic wave. The electron will start moving:
Answer
  1. Along the electric field.
Explanation:
As the electron is at rest initially, only the electric field will exert force on it. There will be no magnetic force on the electron in the stating. Hence, the electron will start moving along the electric field.
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Question 1641 Mark
Pick out the electromagnetic wave which is highly harmful to humans.
Answer
  1. Ultraviolet Rays
Explanation:
Ultraviolet (UV) radiations in large quantities are highly harmful to humans. These rays in solar radiation on reaching earth are absorbed by the ozone layer in the atmosphere. UV rays are produced by special lamps such as mercury and from arc lamps and by very hot bodies like the sun.
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Question 1651 Mark
 Maxwell in his famous equations of electromagnetism introduced the concept of:
Answer
  1. Displacement current
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Question 1661 Mark
Choose the correct answer from the alternatives given. Electromagnetic wave consists of periodically oscillating electric and magnetic vectors:
Answer
  1. In mutually perpendicular planes but vibrating in phase
Explanation:
The Electromagnetic wave consists of the two mutually perpendicular electric and magnetic fields present in the medium and also both being perpendicular to the direction of propagation of the wave. The two fields are in same phase as they obtain their peaks at the same instant.
An electromagnetic wave consists of periodically oscillating electric and the magnetic vector in mutually perpendicular planes but vibrating in phase.
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Question 1671 Mark
 What is the full form of UHF?
Answer
  1. Ultra-high frequency
Explanation:
UHF stands for Ultra high frequency. Cellular phones used radio waves to transmit voice communication in the Ultra high-frequency Band. The UHF band extends from 900 MHz to 5 x 109 Hz or 5000 MHz. Radio waves are produced by oscillating circuits having an inductor and capacitor.
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Question 1681 Mark
The source of electromagnetic waves can be a charge:
Answer
  1. Moving in a circular orbit.
  1. falling in an electric field.
Solution:
Key concept:
  1. An electromagnetic wave can be produced by accelerated or oscillating charge.
  2. An oscillating charge is accelerating continuously, it will radiate electromagnetic waves continuously.
  3. Electromagnetic waves are also produced when fast moving electrons are suddenly stopped by a metal target of high atomic number.
Here, in option (b) charge is moving in a circular orbit.
In circular motion, the direction of the motion of charge is changing continuously, thus it is an accelerated motion and this option is correct.
In option (d), the charge is falling in electric field. If a charged particle is moving in electric field it experiences a force or we can say it accelerates. We know an accelerating charge particle radiates electromagnetic waves. Hence option (d) is also correct.
Also, we know that a charge starts accelerating when it falls in an electric field.
Important points:
  1. In an atom an electron is circulating around the nucleus in a stable orbit, although accelerating does not emit electromagnetic waves; it does so only when it jumps from a higher energy orbit to a lower energy orbit.
  2. A simple LC oscillator and energy source can produce waves of desired frequency
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Question 1711 Mark
The pressure exerted by an electromagnetic wave of intensity I$\Big(\frac{\text{watt}}{\text{m}^2}\Big)$ on a non-reflecting surface is : [c is the velocity of light].
Answer
  1. $\frac{\text{I}}{\text{c}}$
Explanation:
Momentum of a photon
$=\frac{\text{h}}{\lambda}=\frac{\text{h}}{\frac{\text{c}}{\text{v}}}=\frac{\text{hv}}{\text{c}}=\frac{\text{E}}{\text{c}}$
Momentum over unit area
$=\frac{\text{E}}{\text{Ac}}=\frac{\text{I}}{\text{c}}\Big[\text{I}=\frac{\text{E}}{\text{A}}\text{ For wave}\Big]$
Since surface is non reflecting, final momentum of photon = 0, change in momentum $=\frac{\text{I}}{\text{c}}$
So, force per unit area $=\frac{\text{I}}{\text{c}}$
Pressure of radiation $=\frac{\text{I}}{\text{c}}$
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Question 1721 Mark
Maxwell's equation describe the fundamental laws of.
Answer
  1. both (A) and (B)
Explanation:
Maxwell's equation describe the fundamental laws of electricity and magnetism. His equations describe how electric and magnetic fields are generated and altered by each other and by charges and currents.
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Question 1731 Mark
The electric field for a plane, electomagnetic wave travelling in the +y direction is shown in figure.If the electric field of the wave $\overline{\text{E}}$ is in the Z direction , then the $\overline{\text{B}}$ field is.
Image
Answer
  1. In the x direction and in phase with the $\overline{\text{E}}$ field
Explanation:
The wave equation for a plane electric wave traveling in the x direction in space is
$\frac{\delta^2\text{E}}{\delta^2\text{y}}=\frac{1}{\text{c}^2}\frac{\delta^2\text{E}}{\delta\text{t}^2}$
with the same form applying to the magnetic field wave in a plane perpendicular the electric field. Both the electric field and the magnetic field are perpendicular to the direction of travel y.
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Question 1741 Mark
A parallel plate capacitor is charged to $60\ \mu\text{c}$ Due to a radioactive source, the plate loses charge at the rate of $1.8\times10^{-8}\frac{\text{C}}{\text{s}}$ The magnitude of displacement current is :
Answer
The displacement current is that current which comes into play in the region in which the electric field and hence the electric flux is changing with time.
Maxwell found that conduction current $(I)$ and displacement current $(I_d​)$ together have the property of continuity, although individually they may not be continuous.
Maxwell also predicted that this current produces the same magnetic field as a conduction current can produce.
Displacement current is given by
$\text{I}_\text{d}=\frac{\text{dq}}{\text{dt}}=1.8\times10^{-8}\frac{\text{C}}{\text{s}}$
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Question 1751 Mark
The concept of displacement current introduced by Maxwell removes asymmetry between.
Answer
  1. Faraday's law and Ampere' law
Explanation:
Maxwell added the concept of displacement current in AMpere Circuit Law which governs the conduction in the wire of conduction current. After the deviation compass between capacitor Maxwell thought of magnetic lines which would be the result of varying current known as displacement current. So by continuing the displacement in Amperes law, Maxwell was able to show the result of Amperes conduction in circuit moving electrons and also the result of faraday generation of ME waves.
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Question 1761 Mark
Consider the following two statements regarding a linearly polarised, plane electromagnetic wave:
  1. The electric field and the magnetic field have equal average values.
  2. The electric energy and the magnetic energy have equal average values.
Answer
For a linearly polarised, plane electromagnetic wave,
$\text{E}=\text{E}_0\sin\omega\Big(\text{t}-\frac{\text{x}}{\text{c}}\Big)$
$\text{B}=\text{B}_0\sin\omega\Big(\text{t}-\frac{\text{x}}{\text{c}}\Big)$
The average value of either $E$ or Bover a cycle is zero $($average of $\sin(\theta)$ over a cycle is zero$)$.
Also the electric energy density $(U_E)$ and magnetic energy density $(U_B)$ are equal.
$\text{u}_\text{E}=\frac{1}{2}\in_0\text{E}^2=\frac{\text{B}^2}{2\mu_0}=\text{u}_\text{B}$
Energy can be found out by integrating energy density over the entire volume of full space.
As the energy of the electromagnetic wave is equally shared between electric and magnetic field so their average values will also be equal.
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Question 1771 Mark
 Identify the electromagnetic wave which is also known as heatwaves.
Answer
  1. Infrared Waves
Explanation:
Infrared waves are heat radiations also known as heatwaves. These waves are produced by hot bodies and molecules. They do heating because water molecules present in most of the materials readily absorb infrared waves and their thermal motion increases, so they heat themselves and also heat their surroundings.
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Question 1781 Mark
Light wave is travelling along y - direction. If the corresponding E vector at any time along the x - axis, the direction of B vector at that time is along.
Image
Answer
  1. z - axis
Explanation:
Light wave is an electromagnetic wave in which E and B are at right angles to each other as well as at right angles to the direction of wave propagation. So from the given information in the question, the direction of B vector is in positive z direction.
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MCQ 1791 Mark
The oscillating electric and magnetic vectors of an electromagnetic wave are oriented along
  • A
    The same direction but differ in phase by 90°
  • B
    The same direction and are in phase
  • C
    Mutually perpendicular directions and differ in phase by 90°
  • Mutually perpendicular directions and are in phase
Answer
Correct option: D.
Mutually perpendicular directions and are in phase
D
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