Question 1012 Marks
Factorise:
$6 x^2-17 x-3$
$6 x^2-17 x-3$
Answer
View full question & answer→$6 x^2-17 x-3$
$=6 x^2-18 x+x-3$
$\{6 × (-3) = -18, -18 = -18 × 1, -17 = -18 + 1\}$
$= 6x(x - 3) + 1(x - 3)$
$ = (x - 3)(6x + 1)$
$=6 x^2-18 x+x-3$
$\{6 × (-3) = -18, -18 = -18 × 1, -17 = -18 + 1\}$
$= 6x(x - 3) + 1(x - 3)$
$ = (x - 3)(6x + 1)$