Magnitude of the uniform magnetic field, \(B =0.15 \,T\)
Angle between the wire and magnetic field, \(\theta=30^{\circ}\)
Magnetic force per unit length on the wire is given as
\(f=B I \sin \theta\)
\(=0.15 \times 8 \times 1 \times \sin 30^{\circ}\)
\(=0.6\, N\, m ^{-1}\)
Hence, the magnetic force per unit length on the wire is \(0.6 \;N \,m ^{-1}\)
[$m _{p}=1.6 \times 10^{-27} kg , e =1.6 \times 10^{-19} C$ નો ઉપયોગ કરવો.]