Since block is at rest therefore
\(fr - mg =0\) \(........(1)\)
\(F- N =0\) \(..........(2)\)
\(fr \leq \mu N\)
In limiting case
\(fr =\mu N =\mu F\) \(........(3)\)
Using eq. \((1)\) and \((3)\)
\(\therefore \mu F = mg\)
\(\Rightarrow F=\frac{0.5 \times 10}{0.2}=25 N\)
$\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right.$ અને $\left.\tan 37^{\circ}=3 / 4\right)$