\(a t\; t=0 \;\;1 \quad \;\;\;\;\;2\quad \;\;\;\;\;\;\quad 0\)
\(at \;equil.(1-\alpha) \; 2(1-\alpha)\;2\alpha\)
\(Given\,at\,equilibrium\)
\({K_C} = \frac{{{{(2\alpha )}^2}}}{{(1 - \alpha ){{(2 - 2\alpha )}^2}}} = \mathop {\mathop {\frac{{{{(0.8)}^2}}}{{(1 - 0.8){{(1 - 0.8)}^2}}}}\limits^{\alpha = 0.8} }\limits^{2\alpha = 1.6} \)
\( = \frac{{0.64}}{{0.002}}\)
\({K_C} = 80\)
($R = 0.082\, L\, atm\, mol^{-1}\, K^{-1}$, મોલર દળ $S = 32\, g\, mol^{-1}$, મોલર દળ $N = 14\, g\, mol^{-1}$)