\(\,\mathop {{r_{cm}}}\limits^ \to  \, = \,\,(0,\,\,0,\,\,0),\,\,m\,\, = \,\,40\,\,kg,\,\,\,\,\mathop r\limits^ \to  \,\, = \,\,?\)

નવા તંત્રનું દ્રવ્યમાન કેન્દ્ર  \(\,\mathop {{{{\text{r'}}}_{{\text{cm}}}}}\limits^ \to  \,\, = \,\,(3,\,\,3,\,\,3)\)

\(\mathop {{{r'}_{cm}}}\limits^ \to  \, = \,\,\,\frac{{M\,\mathop {{r_{cm}}}\limits^ \to  \, + \,\,m\,\mathop r\limits^ \to  }}{{M\,\, + \,\,m}}\,\,\,\,\)

\((3,\,\,3,\,\,3)\,\, = \,\,\frac{{60\,(0,\,\,0,\,\,0)\,\, + \,\,40\,(x,\,\,y,\,\,z)}}{{60\,\, + \,\,40}}\,\,\,\, = \,\,\frac{{40(x,\,\,y,\,\,z)}}{{100}}\)

\(\therefore \,\,(3,\,\,3,\,\,3)\,\,\, = \,\,\,(0.4\,x,\,\,0.4\,y,\,\,0.4\,z)\)

બંને બાજુના યામ સરખાવતા \(\therefore \,\,(3,\,\,3,\,\,3)\,\,\, = \,\,\,(0.4\,x,\,\,0.4\,y,\,\,0.4\,z)\)

આજ રીતે \({\text{y}}\,\, = \,\,{\text{7}}{\text{.5}}\,\,{\text{m,}}\,\,\,\,\,\,{\text{z}}\,\,\, = \,\,{\text{7}}{\text{.5}}\,\,{\text{m}}\,\) આથી  \(\,\mathop {\text{r}}\limits^ \to  \,\, = \,\,\,(7.5,\,\,7.5,\,\,7.5)\,\,m\)