\(\rho=\frac{ AV }{ I \ell}=\frac{\pi d ^{2} V }{4 I \ell} \quad\left( A =\frac{\pi d ^{2}}{4}\right)\)
\(\therefore \frac{\Delta \rho}{\rho}=\frac{2 \Delta d }{ d }+\frac{\Delta V }{ V }+\frac{\Delta I }{ I }+\frac{\Delta \ell}{\ell}\)
\(\frac{\Delta \rho}{\rho}=2\left(\frac{0.01}{5.00}\right)+\frac{0.1}{5.0}+\frac{0.01}{2.00}+\frac{0.1}{10.0}\)
\(\frac{\Delta \rho}{\rho}=0.004+0.02+0.005+0.01\)
\(\frac{\Delta \rho}{\rho}=0.039\)
\(\%\) error \(=\frac{\Delta \rho}{\rho} \times 100=0.039 \times 100=3.90 \%\)
$Sl$. $No$. | $R\, (\Omega )$ | $l\, (cm)$ |
$1$. | $1000$ | $60$ |
$2$. | $100$ | $13$ |
$3$. | $10$ | $1.5$ |
$4$. | $1$ | $1.0$ |
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