\(v=\sqrt{\frac{Y}{\rho}}=\sqrt{\frac{7.8 \times 10^{10}}{2600}}=5480 \,ml\)
Since rod is clamped at the middle, the middle point is a pressure antinode and free ends are nodes. In the fundamental mode there are no other nodes and antinodes. The length of the rod is therefore half the wavelength.
So, \(\lambda=2 I=2 \,m\)
Frequency \(=\frac{v}{\lambda}=\frac{5480}{2}=2740 \,Hz\)
${y}=1.0\, {mm} \cos \left(1.57 \,{cm}^{-1}\right) {x} \sin \left(78.5\, {s}^{-1}\right) {t}$
${x}>0$ ના ક્ષેત્રમાં ઉગમબિંદુથી નજીકનું નિસ્પંદ બિંદુ ${x}=\ldots \ldots \ldots\, {cm}$ અંતરે હશે.