$p_{s}=732\, \mathrm{mm},\,\, K_{b}=0.52$
$T_{b}^{o}=100\,^{o} \mathrm{C},\,\, p^{o}=760 \,\mathrm{mm}$
$\frac{p^{o}-p_{s}}{p^{o}}=\frac{n_{2}}{n_{1}}$
$\Rightarrow \frac{760-732}{760}=\frac{n_{2}}{100 / 18}$
$\Rightarrow n_{2}=\frac{28 \times 100}{760 \times 18}=0.2046\, \mathrm{mol}$
$\Delta T_{b}=K_{b} \times m$
$T_{b}-T_{b}^{o}=K_{b} \times \frac{n_{2} \times 1000}{W_{A}\,(g)}$
$ T_{b}-100\,^{o} \mathrm{C} =\frac{0.52 \times 0.2046 \times 1000}{100} $
$=1.06 $
$T_{b}=100+1.06 =101.06\,^{o} \mathrm{C} $
(આપેલ, $K_f = 5\,K\, kg\,mol^{-1},$ બેન્ઝોઇક એસિડનું મોલર દળ $= 122\,g\,mol^{-1}$ )