mass of solute $(w)\,=\,120\,g$

mass of solvent $(w)\,=\,1000\,g$

Mol. mass of solute $=60\,g$

density of solution $=\,1.12\,g/ml$

From the given data,

Mass of solution $=\,1000+120=1120\,g$

$d=\frac {Mol.mass}{V}$ or $V=\frac {Mol.mass}{d}$

Volume of solution $V\,=\,\frac {1120}{1.12}\,=\,1000\,ml$ or

$=\,1\,litre$

Now molarity $(M)$ $=\,\frac {W}{Mol.\,mass\times V(lit)}$ $=\,\frac {120}{60\times 1}$ $=\,2\,M$