$AgI$ માટે $log\, K_{sp}$ નું મૂલ્ય શું હશે? (જ્યાં $K_{sp}=$ દ્રાવ્યતા નીપજ)
\({\text{E}}_{{\text{Ag/A}}{{\text{g}}^ \oplus }}^ \circ \, + \,\,E_{{I^ - }}^ \circ {\,_{AgI/Ag}}\,\, = \,\,\frac{{0.059}}{1}\,\log \,\,Ksp\)
\( = \,\, - \,\,0.80\,\, - \,\,0.152\,\, = \,\,\frac{{0.059}}{1}\,\,\log \,\,Ksp\)
\(\log \,\,Ksp\,\, = \,\, - \,\,\frac{{0.952}}{{0.059}}\,\, = \,\, - \,\,16.13\)
$Zn | Zn ^{2+}(0.1\, M ) \| Ag ^{+}(0.01 \,M )| Ag$
[આપેલ $: E_{Z n^{+2}/Z_{n}}^{0}=-0.76 \,V ; E _{A g^{+} / A_{ g }}^{0}=+0.80 \,V ; \frac{2.303 RT }{ F }=0.059$]
$\mathrm{MnO}_4^{-}+\mathrm{H}^{+}+\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \rightleftharpoons \mathrm{Mn}^{2+}+\mathrm{H}_2 \mathrm{O}+\mathrm{CO}_2$
પ્રમાણિત રિડકશન પોટેન્શિયલ નીચે આપેલા છે. $\left(\mathrm{E}_{\mathrm{red}}^{\circ}\right)$
$\mathrm{E}_{\mathrm{MmO}_4^{-} / \mathrm{Mm}^{2+}}^{\circ}=+1.51 \mathrm{~V}$
$\mathrm{E}_{\mathrm{CO}_2 / \mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4}^{\circ}=-0.49 \mathrm{~V}$
જો ઉપરની પ્રક્રિયાને સંતુલન અચળાંક $K_{e q}=10^x$, તરીકે આપેલ હોય તો, $x$ નું મૂલ્ય = ___________. (નજીકનો પૂણુાંક)
$2 \mathrm{H}_{(\mathrm{aq})}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_2(\mathrm{~g})$
${\left[\mathrm{H}^{+}\right]=1 \mathrm{M}, \mathrm{P}_{\mathrm{H}_2}=2 \mathrm{~atm}}$
(Given: $2.303 \mathrm{RT} / \mathrm{F}=0.06 \mathrm{~V}, \log 2=0.3$ )
$(i)\, A3^-\rightarrow A^{2-} + e; E° = 1.5 \,V$
$(ii) \,B^{+}+ e \rightarrow B; E° = 0.5 \,V$
$(iii)\, C^{2+} + e \rightarrow C^{+}; E°= 0.5\, V$
$(iv)\, D \rightarrow D^{2+}+ 2e; E° = -1.15\, V$
$Cr_{(s)} | Cr^{3+}_{(0.1\,M)} | | Fe^{2+}_{(0.01\,M)} | Fe;$
$E^0_{{cr}^{3+} |Cr} = -0.72 \,V,$ $ E^{0}_{{Fe}^{2+}{| Fe}}$ $= -0.42 \,V$