[આપેલ $: R =8.31 \,J \,K ^{-1} \,mol ^{-1}, \log 1.33=0.1239$ $\ln 10=2.3]$
\(t =0 \quad\quad1 \,mol\)
\(t = t\quad \quad(1-0.5) \,mol \quad \quad 0.5 \times 2\,mol\)
\(\quad\quad\quad\quad=0.5 \,mol \quad\quad\quad 1\, mol\)
\(k _{ p }=\frac{\left(\frac{1}{1.5} \times 1\right)^{2}}{\left(\frac{0.5}{1.5} \times 1\right)}=\frac{1}{0.75}=\frac{100}{75}\)
\(=1.33\)
\(\Delta G ^{0}=- RT \ell nk _{ P }\)
\(=-8.31 \times 300 \times \ell n (1.33)=-710.45\, J / mol\)
\(=-710 \,J / mol\).