Therefore three capacitors most be in parallel to get \(6\) in \(\frac{1}{C_{e q}}=\frac{1}{3 C}+\frac{1}{C}+\frac{1}{C}+\frac{1}{C}+\frac{1}{C}\)
\(C_{e q}=\frac{3 C}{13}=\frac{6}{13} \,\mu F\)
$\left[\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9} Nm ^{2} C ^{-2}\right] $ નો ઉપયોગ કરો