\( \mathrm{f}=\mathrm{R} / 2=+15 \mathrm{~cm}\)
Magnification \((\mathrm{m})= \pm \frac{1}{2}\)
For convex mirror, virtual image is formed for real object.
Therefore, \(\mathrm{m}\) is +ve
\( \frac{1}{2}=\frac{f}{f-u} \)
\( u=-15 \mathrm{~cm}\)
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