\(\therefore 0.001=\frac{\Delta V}{300} \times 100\)
\(\Rightarrow \Delta V=3 \times 10^{-3}\)
According to Heisenberg uncertainty principle,
\(\Delta x \cdot m \Delta V \geq \frac{h}{4 \pi}\)
\(\Rightarrow \Delta x=\frac{h}{4 \pi m \Delta V}\)
\(\Rightarrow \Delta x =\frac{6.63 \times 10^{-34}}{4 \times 3.14 \times 9.10^{-31} \times 3 \times 10^{-3}}\)
\(=1.92 \times 10^{-2} \mathrm{\,m} \)
($\lambda$ એ ઇલેક્ટ્રોનના તરંગ સાથે સંકળાયેલી તરંગલંબાઈ છે)