==> \(\frac{{dm}}{{dt}} = \frac{{KA}}{l}\,\left( {\frac{{\Delta \theta }}{L}} \right)\). Let the desire point is at a distance \( x\) from water at \(100°C\) . ( Rate of ice melting = Rate at which steam is being produced
==> \({\left( {\frac{{dm}}{{dt}}} \right)_{Steam}} = {\left( {\frac{{dm}}{{dt}}} \right)_{Ice}}\)
==> \({\left( {\frac{{\Delta \theta }}{{Ll}}} \right)_{Steam}} = {\left( {\frac{{\Delta \theta }}{{Ll}}} \right)_{Ice}}\)
==> \(\frac{{(200 - 100)}}{{540 \times x}} = \frac{{(200 - 0)}}{{80\,(3.1 - x)}}\)
==> \(x = 0.4 m = 40 cm\)
કારણ : બે પાતળા ધાબળા વચ્ચેનું હવાનું પડને લીધે જાડાઈ વધે છે.