\(\theta=\frac{r}{L} \phi\)
\(\theta=\frac{1 \times 10^{-3} \times 30^{\circ}}{5}\) \(\left\{\begin{array}{l}\text { Where } \\ \theta=\text { Angle of shear } \\ \phi=\text { Angle of twist } \\ r=\text { Radius of rod } \\ I=\text { length or rod }\end{array}\right.\)
\(\theta=6 \times 10^{-3}\)