Equivalent resistance \(R = \frac{{3 \times (3 + 3)}}{{3 + (3 + 3)}} = 2\,\Omega \)
Current \(i = \frac{2}{2} = 1\,A.\) So,\({i_1} = 1 \times \left( {\frac{3}{{3 + 6}}} \right) = \frac{1}{3}\,A\).
Potential difference between \(A\) and \(B =\frac{1}{3} \times 3 = 1\,volt.\)