A $72 \; \Omega$ galvanometer is shunted by a resistance of $8 \; \Omega$. The percentage of the total current which passes through the galvanometer is $.....$
JEE MAIN 2022, Medium
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$S=\frac{R_{G}}{\frac{I}{I_{g}}-1}$
$8=\frac{72}{\frac{I}{I_{g}}-1}$
$\frac{I}{I_{g}}-1=9$
$\frac{I}{I_{g}}=10 \Rightarrow \frac{I_{g}}{I}=\frac{1}{10} \quad \% I=\frac{I_{g}}{I} \times 100=10 \%$
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