A metal ring of radius $r = 0.5 \,\,m $ with its plane normal to a uniform magnetic field $B$ of induction $0.2 T$ carries a current $I = 100\,\, A$. The tension in newtons developed in the ring is:
Medium
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$\mathrm{F}=\mathrm{I} \int \mathrm{d} \vec{\ell} \times \overrightarrow{\mathrm{B}}$
$=\mathrm{I}(2 r \hat{\mathrm{i}}) \times(-0.2 \hat{\mathrm{k}})=20 \mathrm{j}$
Magnetic force is in $+ve$ $y$ direction
So balancing force on semi-circular ring we get
$2 T=20$
$T=10 N$
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