A $90\, cm$ long solenoid has six layers of windings of $450\, turns$ each. If the diameter of solenoid is $2.2\, cm$ and current carried is $6\, A$, then the magnitude of magnetic field inside the solenoid, near its centre is
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For six layers of windings the total number of turns
$=6 \times 450=2700$
Now number of turns per unit length
$\mathrm{n}=\frac{\mathrm{N}}{l}=\frac{2700}{90 \times 10^{-2}}=3000$
$[$ Then the field inside the solenoid near the centre $]$
$\mathrm{B}=\mu_{0} \mathrm{nI}=4 \pi \times 10^{-7} \times 3000 \times 6$
$=72 \pi \times 10^{-4}\, \mathrm{T}=72 \pi \mathrm{G}$
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