A block of mass $10\, kg$ is kept on a rough inclined plane as shown in the figure. A force of $3\, N$ is applied on the block. The coefficient of static friction between the plane and the block is $0.6$. What should be the minimum value of force $P$, such that the block does not move downward? (take $g = 10\, ms^{-2}$) ........ $N$
A$32$
B$18$
C$23$
D$25$
JEE MAIN 2019, Medium
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A$32$
a $\begin{array}{l}
For\,equilibrium\,of\,the\,block\,net\,force\,\\
should\,be\,zero.\,Hence\,we\,can\,write.\\
mg\,\sin \theta + 3 = p + friction\\
mg\sin \theta + 3 = p + \mu mg\,\cos \,\theta .\\
After\,solving,\,we\,get,\,p = 32N.
\end{array}$
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