MCQ
A block of mass m initially at rest is dropped from a height $h$ on to a spring of force constant $k$. the maximum compression in the spring is $x$ then
  • A
    $mgh = \frac{1}{2}k{x^2}$
  • $mg(h + x) = \frac{1}{2}k{x^2}$
  • C
    $mgh = \frac{1}{2}k{(x + h)^2}$
  • D
    $mg(h + x) = \frac{1}{2}k{(x + h)^2}$

Answer

Correct option: B.
$mg(h + x) = \frac{1}{2}k{x^2}$
b
(b) Change in gravitational potential energy
$=$ Elastic potential energy stored in compressed spring
$ \Rightarrow mg(h + x) = \frac{1}{2}k{x^2}$

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