A block pressed against the vertical wall is in equilibrium. The minimum coefficient of friction is:-
Medium
Download our app for free and get started
$\mu m g \leq m g-\frac{m g}{2}$
$\mu_{\min }=\frac{1}{2}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionMaximum value of static friction is called
- 2A cyclist riding the bicycle at a speed of $14\sqrt 3 ms^{-1}$takes a turn around a circular road of radius $20\sqrt 3 $ m without skidding. Given $g = 9.8 ms^{-2},$ what is his inclination to the vertical ....... $^o$View Solution
- 3Two particles of equal masses are revolving in circular paths of radii ${r_1}$ and ${r_2}$ respectively with the same speed. The ratio of their centripetal forces isView Solution
- 4View SolutionWhich one of the following statements is incorrect?
- 5A heavy box is solid across a rough floor with an initial speed of $4 \,m / s$. It stops moving after $8$ seconds. If the average resisting force of friction is $10 \,N$, the mass of the box (in $kg$ ) is .....View Solution
- 6Someone is using a scissors to cut a wire of circular cross section and negligible weight. The wire slides in the direction away from the hinge until the angle between the scissors blades becomes $2 \alpha$. The friction coefficient between the blades and the wire, is :-View Solution
- 7A fireman of mass $60\, kg$ slides down a pole. He is pressing the pole with a force of $600 \,N$. The coefficient of friction between the hands and the pole is $0.5$, with what acceleration will the fireman slide down ........ $m/s^2$View Solution
- 8A block of $10 \,kg$ mass is placed on a rough inclined surface as shown in figure. The acceleration of the block will beView Solution
- 9View SolutionA block is stationary on a rough inclined plane. How many forces are acting on the block?
- 10A block of mass $m$ is placed on a surface with a vertical cross section given by $y = \frac{{{x^3}}}{6}$ If the coefficient of friction is $0.5$,the maximum height above the ground at which the block can be placed without slipping is:View Solution