c
(c) $\frac{{60 - 50}}{{10}} = K\left( {\frac{{60 + 50}}{2} - 25} \right)$….$.(i)$
$\frac{{50 - \theta }}{{10}} = K\left[ {\frac{{50 + \theta }}{2} - 25} \right]$…..$(ii)$
On dividing, we get $\frac{{10}}{{50 - \theta }} = \frac{{60}}{\theta } $
$\Rightarrow \theta = {42.85^o}C$