A bright object 50mm high stands on the axis of a concave mirror of focal length 100mm and at a distance of 300mm from the concave mirror. How big will the image be?
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$h _1=50 mm, f =-100 mm, u =-300 mm, h _1=?$
We have.$\frac{1}{\text{v}}+\frac{1}{\text{u}}=\frac{1}{\text{f}}$
$\frac{1}{\text{v}}+\frac{1}{(-300)}=\frac{1}{(-100)}$
$\frac{1}{\text{v}}=\frac{1}{300}-\frac{1}{100}$
$\frac{1}{\text{v}}=\frac{-200}{3000}$
$\frac{1}{\text{v}}=-150\text{cm}$
$\text{v}=-150\text{cm}$
$-\frac{-150}{-300}=\frac{\text{h}_2}{50}$
The image will be 25mm high.
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