A capacitor having capacitance $C$ is charged to a voltage $V$. It is then removed and connected in parallel with another identical capacitor which is uncharged. The new charge on each capacitor is now
A$CV$
B$CV / 2$
C$2 CV$
D$CV / 4$
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B$CV / 2$
b (b) Charge flows to second capacitor until the potential is same i.e. $V/2$. So new charge = $CV/ 2$
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