A capacitor of $4\, \mu F$ is connected to a $15\, V$ supply through $1$ mega ohm resistance. The time taken by the capacitor to charge upto $63.2\%$ of its final charge will be......$s$
Medium
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$63.2\% = {\rm{RC}} = {10^6}x\,4\,x{10^{ - 6}} = 4{\mkern 1mu} \,{\rm{s}}$
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