A charge $q$ is spread uniformly over an insulated loop of radius $r$ . If it is rotated with an angular velocity $\omega $ with respect to normal axis then the magnetic moment of the loop is
JEE MAIN 2018, Medium
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Magnetic moment, $\mu \, = \,IA\, = \,\frac{{qv}}{{2\pi r}}(\pi {r^2})$
or, $\mu \,\, = \,\,\frac{{qr\omega }}{{2\pi r}}(\pi {r^2})\, = \,\frac{1}{2}\,q{r^2}\omega $
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